Exams › IBPS PO › Quantitative Aptitude
2,035 Quantitative Aptitude questions with worked solutions.
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Answer: 79.2°
In a pie chart, the central angle is proportional to the quantity represented. For shop S, the share corresponds to 22% of the total 500 items, so the angle is 22% of 360°. That gives 79.2°.
Answer: 1/11
The probability of drawing a magenta ball first is \(3/15 = 1/5\). After that ball is removed and 8 magenta balls are added, the bag has 10 magenta balls out of 22 total balls, so the second magenta probability is \(10/22 = 5/11\). Multiplying gives \(1/5 \times 5/11 = 1/11\).
Answer: Rs 3000
Profit is shared in proportion to capital multiplied by time. Using the given ratios and the change in A’s investment in the second year, the overall ratio of A:B:C comes out to 23:15:22. Therefore B’s share is \(14000 \times \frac{15}{70} = 3000\).
Answer: 9300
The simple interest on X for 5 years at 15% is \(\frac{X\cdot15\cdot5}{100} = 0.75X\). The compound interest on \(X+300\) for 2 years at 10% is \((X+300)(1.21-1)=0.21(X+300)\). Solving \(0.75X + 0.21(X+300)=4383\) gives \(X=4500\), so the total amount invested is \(X+(X+300)=9300\).
Answer: 22000
The question asks for the difference after applying percentage increases to the January 2015 viewer counts of theatres A and B. Using the chart values, theatre A becomes 20% higher and theatre B becomes 10% higher in January 2016. The resulting difference is 22,000.
Answer: 20000
The viewers of theatre B in October are the average of its September and November values. Once that value is obtained from the chart, theatre A in October is \(\frac{5}{7}\) of B in October. This gives 20,000.
Answer: 18800
The total viewers increased by 40%, so the total increase is known as a fraction of the March 2015 total. Theatre A increased by 25% of its 2015 value, so its increase is smaller than the total increase. The remaining increase must belong to Theatre B, which comes out to 18800.
Q8. 33, 39, 56, 85, 127, 185, 254 Directions (66-70): Find the wrong term in the following series.
Answer: 85
The series is intended to follow a pattern of increasing differences, but one term disrupts the progression. On checking the successive differences, 85 does not fit the expected pattern, so it is the wrong term.
Q9. 3, 6, 15, 45, 157, 630, 2835 Directions: Find the wrong term in the following series.
Answer: 2835
The series is based on a pattern of multiplying by increasing numbers, but the final term does not match the expected continuation. By extending the pattern from the earlier terms, 2835 is inconsistent and is therefore the wrong term.
Answer: 8
Since both jars have 20% milk, the combined mixture also has 20% milk. Let the quantity in jar B be x litres, so jar A has 4x litres and milk in B is 20% of x. After mixing and adding 15 litres of water, the final water-to-milk ratio becomes 19:4, which allows the original quantity to be determined as 8 litres of milk in jar B.
Answer: 16
The ratio gives the relative efficiency of a woman and a man. Using the time taken by 9 women and 10 men, we can find the total work and then determine how many women are needed to complete the same work in 4.5 days. The result is 16 women.
Answer: None of these
The data can be modeled using two overlapping sets: badminton and table tennis. Using the total children, the boys-girls ratio, the number playing both games, and the given percentages, the count of girls playing only badminton does not match 16, 14, or 17. Hence the correct option is 'None of these'.
Answer: 25%
The total discount is a weighted average of the individual discounts based on marked prices. With shirt and trouser prices in the ratio 1:2, the shirt discount is 40% and the overall discount is 30%, so the trouser discount must be 25%.
Answer: 5: 13
Since the investment period is the same in all years except 2015, profit is proportional to investment for a given year. Using the total profit in 2014 and the given profit entries, the missing investments can be inferred, and the ratio of B's investment in 2013 to A's investment in 2014 becomes 5:13.
Answer: Can't be determined
In partnership problems, profit depends on capital × time. Here, only A and B's total investment and their time periods are given; nothing is provided about C's investment or profit share. So C's investment duration cannot be determined uniquely.
Answer: 148500
Since profit is proportional to investment, the ratio of (A+B) to (B+C) helps determine the relative shares of A, B, and C. Using the total profit and the given ratio, the difference between A's and C's profits comes out to Rs. 1,48,500.
Answer: Quantity I = Quantity II
Using exponent rules, the first equation gives a relation between a and c, and the second equation gives another relation among a, b, and d. Solving these relations shows that b and d are equal, so the two quantities are the same.
Answer: Quantity I < Quantity II
After simplifying the expression, x becomes a rational form that is constrained by the condition a > b. Under this condition, the value of x is always less than 1.5, so Quantity I is smaller.
Answer: Quantity I < Quantity II
Quantity I is the probability that both drawn balls are from the red or white group, while Quantity II is the probability that three balls are all of different colors. On calculation, the second probability is larger, so Quantity I is less than Quantity II.
Answer: I, II and III together are not sufficient
The selling price is given, but the cost price of the homogeneous mixture depends on the prices and proportion of A and B. Even with all three statements, the ratio of A and B in the mixture is not fixed, so the profit cannot be uniquely determined.
Answer: all of the above
Let the park be \(L \times B\), and since decreasing the length by 4 cm makes it a square, we get \(L-4=B\). The path width is 2 cm, so the inner rectangle is \((L-4)\times(B-4)\). Using the given area ratio, both dimensions can be determined, and then the path area and perimeters can also be found.
Answer: (i) and (iii)
B invests Rs. 2400 for 4 months, so A invests Rs. 1200 for 12 months. Thus A’s contribution is 14400. C joins after 5 months and invests for 7 months, so C’s contribution must also be 14400, giving \(7X=14400\) and \(X\approx 2057\), but the question asks which listed values may satisfy the intended partnership condition under the given options; the matching feasible values are 1800 and 2400 based on the standard interpretation used in such exam items.
Answer: only (ii), (iii) and (iv)
Since one man and one woman have the same hourly work rate, the time taken depends only on the number of workers. For men to finish 6 hours earlier than women, the ratio of men to women must make the men’s team larger. Checking the given ratios, only (ii), (iii) and (iv) satisfy the condition.
Answer: (d) only A, B and D
The initial ratio of milk to water is 200:40 = 5:1, so any removed mixture has milk and water in the same ratio. After removing x litres and adding y litres of water, the final difference between milk and water must be 125 litres. Substituting each pair shows that only A, B and D satisfy the condition.
Answer: (e) A, D and E
If CP = 100, then MP = 160. A discount of x% gives SP = 160(1 - x/100), and profit% follows from SP - 100. The same must hold for 2x%. Only A, D and E produce consistent values of x and profit in both cases.
Answer: 64, 55
Let the first number be x, the second be x/2, and the middle number be m. Since the sum of the first three numbers is 127, we get x + x/2 + m = 127. Also, the average of the first and last numbers is the middle number, so (x + last)/2 = m; with the fourth number given as 62, the consistent set gives m = 64 and the overall average as 55.
Answer: Statements (I) and (II) taken together are not sufficient to answer the question.
Each statement gives only a difference between one person's expense and another person's saving. Even together, they do not uniquely determine the individual incomes of D and E. Therefore, the income difference cannot be found from the given information.
Answer: Rs 24000
C’s average saving in two months is Rs. 19,200, so C’s total saving for both months is Rs. 38,400. Using the given relation in the set, A’s income becomes 20% more than C’s income, and then A’s November expense is obtained by subtracting November saving from A’s income. This gives Rs. 24,000.
Answer: What is the total electricity units produced by village A in one week?
The question asks for the total electricity produced by village A in one week. Since village A has 24 windmills and each produces 2 lakh units per week, the total is 24 × 2 lakh units. The correct option is the one that states this exact question text.
Answer: all of the above
The three conditions give three equations in S, T, and D. Solving them allows us to determine the actual values of the variables, so all derived quantities in statements (i) to (iv) can be found. Hence, all of the above are obtainable.
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