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IBPS PO Quantitative Aptitude: Percentages questions with solutions

9 questions with worked solutions.

Questions

Q1. What will come in place of the question mark (?) in the following equation? 35% of 300 - \(\sqrt{?}\) = 64% of 250 - 30% of 450

  1. 2500
  2. 3600
  3. 4900
  4. 6400

Answer: 6400

Compute the right side: 64% of 250 = 160 and 30% of 450 = 135, so the right side is 25. Also, 35% of 300 = 105, so \(105 - \sqrt{?} = 25\), giving \(\sqrt{?} = 80\). Therefore, ? = 6400.

Q2. In a coaching institute, there are 300 students. \(\frac{3}{20}\) of the total number of students are enrolled in Mathematics coaching. The number of students enrolled in English coaching is the same as the number enrolled in Mathematics coaching. The number of students enrolled in Chemistry coaching is 15 more than the number enrolled in English coaching. The number of students enrolled in Computer coaching is 24 more than the number enrolled in Chemistry coaching. The remaining students are enrolled in Physics coaching. If 40% of the students enrolled in Mathematics and 60% of the students enrolled in English are female students, then find the total number of male students enrolled in Mathematics and English together.

  1. 45
  2. 27
  3. 18
  4. 23

Answer: 45

Mathematics students = \(\frac{3}{20} \times 300 = 45\). English students are also 45. Female students in Mathematics = 40% of 45 = 18, and in English = 60% of 45 = 27. So male students together = \((45-18) + (45-27) = 27 + 18 = 45\).

Q3. An amount is divided among Deepak, Shivam, and Prashant. The amount received by Deepak is ₹40 more than 40% of the total amount, and the amount received by Shivam is ₹5 more than 25% of the total amount, while the amount received by Prashant is 32% of the total amount. Find the amount received by Shivam.

  1. ₹480
  2. ₹380
  3. ₹540
  4. ₹450

Answer: ₹380

Let total amount be $T$. Then Deepak gets $0.4T+40$, Shivam gets $0.25T+5$, and Prashant gets $0.32T$. Their sum equals $T$, so $0.97T+45=T$, giving $T=1500$ and Shivam's share $=0.25(1500)+5=380$.

Q4. What will come in place of the question mark (?) in the following equation? 65% of 400 + 35% of 600 = ?

  1. 430
  2. 510
  3. 450
  4. 470

Answer: 470

65% of 400 = 260 and 35% of 600 = 210. Their sum is 470, so the correct answer is 470.

Q5. 49% of 180 - 70% of 120 = 9 - ?

  1. 4.2
  2. 4.8
  3. 4.9
  4. 4.6

Answer: 4.8

49% of 180 is 88.2 and 70% of 120 is 84, so the left side becomes 4.2. Therefore, 9 - ? = 4.2, giving ? = 4.8.

Q6. Rahul gives 20% of some amount to his wife and again 20% of the remaining amount to charity. Then he has only ₹12,800 left with him. What was Rahul’s initial amount?

  1. 20,000
  2. 30,000
  3. 40,000
  4. 50,000

Answer: 20,000

After giving 20% to his wife, Rahul has 80% left. He then gives 20% of the remaining amount to charity, so 80% of that remains, meaning final amount = 0.8 × 0.8 × original = 0.64 × original. Since 0.64x = 12,800, the original amount is 20,000.

Q7. 65% of 480 - ? + 175 = 350

  1. 125
  2. 129
  3. 137
  4. 147

Answer: 137

65% of 480 is 312. Substituting into the equation gives 312 - ? + 175 = 350, so 487 - ? = 350. Therefore, ? = 137.

Q8. Akash spends 5% of his monthly salary on rent and lends 35% to Vikas. Out of the remaining amount, he spends 30% on food and saves the rest. If his savings are ₹25,200, then what is Akash's monthly salary?

  1. 40,000
  2. 30,000
  3. 50,000
  4. 60,000

Answer: 60,000

After spending 5% on rent and lending 35%, Akash has 60% of his salary left. He spends 30% of that on food, so he saves 70% of 60%, i.e. 42% of his salary. Since 42% equals ₹25,200, the monthly salary is ₹60,000.

Q9. 200 students from school A and 180 from B passed. 20% from A and 10% from B did not pass. How many appeared from both?

  1. 420
  2. 360
  3. 450
  4. 400

Answer: 450

School A: 80% passed → total=200/0.8=250. School B: 90% passed → total=180/0.9=200. Both schools: 250+200=450.

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