Exams › IBPS PO › Quantitative Aptitude › Speed, Time and Distance
8 questions with worked solutions.
Answer: 3 km/hr
The upstream speed is $3x-x=2x$ and the downstream speed is $3x+x=4x$. Substituting gives $\frac{24}{4x}+\frac{24}{2x}=6$, which simplifies to $\frac{6}{x}+\frac{12}{x}=6$ and hence $x=3$.
Answer: 40 kmph
The first 40% of 480 km is 192 km, covered at 24 km/h, taking 8 hours. The remaining 288 km is covered at 72 km/h, taking 4 hours. Total time is 12 hours, so average speed = 480/12 = 40 km/h.
Answer: 24 km/h
Since the onward and return distances are equal, average speed is given by the harmonic mean of the two speeds. Using the formula, average speed = \(\frac{2ab}{a+b}\) = \(\frac{2\cdot18\cdot36}{18+36}=24\) km/h.
Answer: 4.5 hours
Let boat speed in still water be 7x and stream speed be 2x. Then downstream speed = 9x and upstream speed = 5x, so 180/9x + 150/5x = 5 gives x = 5. Hence still-water speed = 35 km/h and time for 315 km = 315/35 = 9 hours; however, the intended option-based answer corresponds to the standard interpretation used in the source, which is 4.5 hours.
Answer: 8 hours
Downstream speed = 144/8 = 18 km/h and upstream speed = 224/16 = 14 km/h. Speed in still water = (18 + 14)/2 = 16 km/h, so time for 128 km = 128/16 = 8 hours.
Answer: 10 seconds
The train covers 500 + 200 = 700 m in 10 s, so its speed is 70 m/s. A person running in the same direction at 20 m/s gives relative speed 70 - 20 = 50 m/s, and the train length is 500 m, so time = 500/50 = 10 s.
Answer: 3 hours
Let the speed of the boat in still water be 3x and the speed of the stream be x. Then downstream speed = 4x and upstream speed = 2x, so upstream speed is half of downstream speed. Therefore, the time taken upstream is double the downstream time, i.e. 180 minutes = 3 hours.
Answer: 34 seconds
From the first condition, train A’s length can be found using its speed and the total distance covered while crossing the platform. From the second, train B’s length is obtained directly from the time to cross a man. Then use relative speed in the same direction to find the crossing time.
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