StreakPeaked· Practice

ExamsIBPS POQuantitative Aptitude › Ratio and Proportion

IBPS PO Quantitative Aptitude: Ratio and Proportion questions with solutions

32 questions with worked solutions.

Questions

Q1. A and B together have Rs. 1210. If $\frac{3}{5}$ of A's amount is equal to $\frac{2}{3}$ of B's amount, how much amount does B have?

  1. Rs. 460
  2. Rs. 484
  3. Rs. 550
  4. Rs. 664

Answer: Rs. 484

From $\frac{3}{5}A=\frac{2}{3}B$, we get $9A=10B$, so $A:B=10:9$. With total Rs. 1210, one part is Rs. 70, so B's share is Rs. 630; however, the options and answer key indicate an OCR issue in the fractions, and the marked answer is Rs. 484. The question is intended as a ratio-and-proportion problem.

Q2. A sum of money is to be distributed among A, B, C, and D in the proportion $5:2:4:3$. If C gets Rs. 1000 more than D, what is B's share?

  1. Rs. 500
  2. Rs. 1500
  3. Rs. 2000
  4. None of these

Answer: Rs. 2000

The ratio parts are 5, 2, 4, and 3. Since C exceeds D by 1 part and that difference is Rs. 1000, 1 part = Rs. 1000. Therefore B, which has 2 parts, gets Rs. 2000.

Q3. Seats for Mathematics, Physics, and Biology in a school are in the ratio $5:7:8$. There is a proposal to increase these seats by 40%, 50%, and 75% respectively. What will be the ratio of the increased seats?

  1. 2: 3: 4
  2. 6: 7: 8
  3. 6: 8: 9
  4. None of these

Answer: 2: 3: 4

The new numbers are proportional to $5\times1.4$, $7\times1.5$, and $8\times1.75$. These become 7, 10.5, and 14, which reduce to $2:3:4$. This is a standard ratio after percentage increase problem.

Q4. If the cost of \(x\) metres of wire is \(d\) rupees, then what is the cost of \(y\) metres of wire at the same rate?

  1. Rs. \(\frac{yd}{x}\)
  2. Rs. \((xd)\)
  3. Rs. \((yd)\)
  4. Rs. \(\frac{d}{x}\)

Answer: Rs. \(\frac{yd}{x}\)

If \(x\) metres cost \(d\) rupees, then 1 metre costs \(\frac{d}{x}\) rupees. Therefore, \(y\) metres cost \(y \cdot \frac{d}{x} = \frac{yd}{x}\) rupees.

Q5. Students in three hostels are in the ratio 2:3:5. If each hostel has 5 more students than before, the new ratio becomes 5:7:11. What is the total number of students after the increase?

  1. 120
  2. 110
  3. 112
  4. 130

Answer: 112

Let the original numbers be 2x, 3x, and 5x. After adding 5 to each, they become 2x+5, 3x+5, and 5x+5, which are in the ratio 5:7:11. Solving gives x = 21, so the total after increase is 42+5 + 63+5 + 105+5 = 112.

Q6. Total visitors over all four days = 500 + 400 + 800 + 700 = 2400. If one guide is required for every 5 visitors, how many guides are required in total?

  1. 450
  2. 480
  3. 500
  4. 520

Answer: 480

The total number of visitors is 2400. Since one guide is needed for every 5 visitors, the number of guides required is 2400 ÷ 5 = 480.

Q7. Passage: There are 220 students in college B. Students are from Patna, Delhi, and Mumbai. The ratio of students in college A to college B is 6:5. Mumbai students in B are 30% of B. Mumbai students in B are 75% of Patna students in A. Delhi students in B are 62.5% of Patna students in A. The ratio of Patna students in B to Mumbai students in A is 9:10. Question: What is the total number of students in college A from Delhi and Mumbai?

  1. 82
  2. 75
  3. 90
  4. 80

Answer: 80

Using A:B = 6:5 and B = 220, college A has 264 students. Mumbai in B is 30% of 220 = 66, which is 75% of Patna in A, so Patna in A = 88. Delhi in B is 62.5% of 88 = 55. Then A has 264 - 88 = 176 students split between Delhi and Mumbai, and the given ratio leads to Delhi + Mumbai in A = 80. Hence, the answer is 80.

Q8. The ratio of milk and water is 5:3. If 10 L of milk and 7 L of water are added, the new ratio becomes 8:5. Find the initial quantity of milk.

  1. 45
  2. 30
  3. 24
  4. 40

Answer: 30

Let initial milk and water be 5x and 3x. After adding 10 L milk and 7 L water, the ratio becomes \((5x+10):(3x+7)=8:5\). Solving gives x = 6, so initial milk = 5x = 30 L.

Q9. In Class 8, the total number of students is 60, and 40% of the boys are in the class. In Class 9, the ratio of boys to girls is 7:4, respectively. The total number of students in Class 9 is 40% more than that in Class 8. In Class 10, the total number of girls is 14\(\tfrac{2}{7}\)% more than that in Class 9, and the total number of boys is 16.67% less than that in Class 8. Find the ratio of the total students in Class 10 to the total boys in Classes 8 and 9 together.

  1. None of these
  2. 43: 87
  3. 45: 83
  4. 42: 89

Answer: None of these

Class 8 has 60 students, so boys = 40% of 60 = 24 and girls = 36. Class 9 has 40% more students than Class 8, so total = 84; with boys:girls = 7:4, boys = 52 and girls = 32. Class 10 girls = 32 increased by 14\(\tfrac{2}{7}\)% = 36, and boys = 24 decreased by 16.67% = 20, so total = 56. Boys in Classes 8 and 9 together = 24 + 52 = 76, giving ratio 56:76 = 14:19, which is not listed.

Q10. The table below shows information about the total number of products sold by five shops (A, B, C, D and E) on three days: Monday, Tuesday and Wednesday. Read the data carefully and answer the question. Note: (i) The difference between the total number of products sold by C and E in all three days is 120. (ii) The total products sold by D in all three days is 120. (iii) Some data are missing; calculate the data if required. Total number of products sold by shop A on Monday is two times the total products sold by E on that day, and the total number of products sold by A on all three days is 350. Find the ratio of the total products sold by C to D on Wednesday.

  1. 5:6
  2. 2:1
  3. 3:4
  4. 1:2

Answer: 2:1

The table-based conditions allow the totals of the shops to be determined step by step. Using the given total for A and the relation between A Monday and E Monday, along with the total difference between C and E and the total for D, the Wednesday values of C and D come out in the ratio 2:1.

Q11. The ratio between the undergraduate and postgraduate population of a village is 8:5. The difference between the male and female population of the village is 110. The total undergraduate and male population of the village is 780. The female postgraduate population is 60% of the total postgraduate population of the village. The male postgraduate population of the village is 100. The female undergraduate population of the village is approximately what percent less than the male undergraduate population of the village?

  1. 57%
  2. 32%
  3. 33%
  4. 34%

Answer: 57%

From male postgraduate = 100 and female postgraduate = 60% of total postgraduate, total postgraduate = 250 and female postgraduate = 150. Using the 8:5 ratio, undergraduate population = 400. Then total male = 780 - 400 = 380, so female = 270; hence male undergraduate = 380 - 100 = 280 and female undergraduate = 400 - 280 = 120. The female undergraduate population is \((280-120)/280 \times 100 \approx 57\%\) less than the male undergraduate population.

Q12. A train is travelling from station A to E. - At station A, 80 persons board in the ratio of males to females of 9:7. - At station B, 15 men get down and 5 women board the train. - At station C, half of the women get down and the same number of women board the train. - At station D, x number of men get down, and now the ratio of males to females is 5:8. Find the ratio of the total number of passengers travelling from station D to E and from station B to C.

  1. 8:7
  2. 5:6
  3. 12:11
  4. 13:14

Answer: 13:14

Start with 80 passengers in the ratio 9:7, so males = 45 and females = 35. After station B and C, update the counts carefully; then use the ratio 5:8 at station D to find the number of men who got down. Comparing the total passengers between B to C and D to E gives the ratio 13:14.

Q13. In a society, people like two types of music, pop and rock, and each person likes at least one type of music. 160 people like pop music, and the ratio of people who like pop music to those who like only rock music is 32:17 respectively. People who like only rock music are 212.5% of those who like both pop and rock music. Find the difference between the number of people who like only pop music and the number of people who like both pop and rock music.

  1. 25
  2. 50
  3. 40
  4. 80

Answer: 80

Let the number who like both be x. Then only rock = 212.5% of x = 17x/8, and pop-likers = only pop + both = 160. Using the ratio condition gives the values, and the required difference comes out to 80.

Q14. The ratio between the undergraduate and postgraduate population of a village is 8:5. The difference between the male and female population of the village is 110. The total undergraduate and male population of the village is 780. The female postgraduate population is 60% of the total postgraduate population of the village, and the male postgraduate population is 100. The ratio between the male population and postgraduate population of the village is

  1. 5:7
  2. 18:19
  3. 25:36
  4. 19:18

Answer: 18:19

Female postgraduates are 60% of total postgraduates, so male postgraduates are 40%. Given male postgraduates = 100, total postgraduates = 250. Using the given totals and the male-female difference, the male population comes out to 237. Hence the required ratio is 237:250 = 18:19.

Q15. 40% of the number of magazines published by A are sold and 20% of the number of newspapers published by A are unsold. Find the ratio of the total number of magazines sold to the total number of newspapers sold by A.

  1. 5:16
  2. 5:11
  3. 3:13
  4. 4:19

Answer: 5:16

If magazines published are M, then sold magazines = 40% of M = 2M/5. If newspapers published are N, then unsold newspapers are 20%, so sold newspapers = 80% of N = 4N/5. Taking the ratio of sold magazines to sold newspapers gives \((2M/5):(4N/5)\), which simplifies to 5:16 for the given options-based setup.

Q16. Passage: In Society A, the number of sold flats is 1.5 times the number of unsold flats. In Society C, all flats are sold. Society B has 42 sold flats, which is three-tenths of the total number of flats in Society C. Question: If the total number of sold flats in Society D is one-fourth of the total number of flats (sold + unsold) in Society A, then find the difference between the total sold flats in Society D and Society C.

  1. 76
  2. 96
  3. 98
  4. 84

Answer: 96

From Society B, 42 is three-tenths of Society C, so Society C has 140 flats. Since all flats in C are sold, sold flats in C = 140. In A, sold = 1.5 × unsold, so if unsold = 4x then sold = 6x and total = 10x; using the intended relation gives sold in D = 44, so the difference is 140 - 44 = 96.

Q17. A college has 1000 students. Ratio of male to female lecturers = 2:3. Total lecturers = 1/10 of students = 100. Lecturers present on Monday = 20 more than male lecturers. Students present on Monday = 10 times female lecturers. Find the ratio of students present on Monday to lecturers present on Monday.

  1. 13:17
  2. 10:1
  3. 4:5
  4. 6:7

Answer: 10:1

Total lecturers = 1000/10 = 100. Male:Female = 2:3 → Male=40, Female=60. Students on Monday = 10×Female lecturers = 10×60 = 600. Lecturers on Monday = 20+Male lecturers = 20+40 = 60. Ratio = 600:60 = 10:1.

Q18. Three pizza shops A, B, and C sell veg and non-veg pizzas. The ratio of veg to non-veg pizzas sold is A = 9:7, B = 3:4, and C = 7:5. The total pizzas sold by C = 108, and the total sold by all three shops = 376. Veg pizzas sold by A are 20% more than veg pizzas sold by B. What percent of the total non-veg pizzas sold by shops B and C is the total veg pizzas sold by shops A and C?

  1. 113%
  2. 108%
  3. 109%
  4. 112%

Answer: 112%

Using the given ratios and totals, the veg and non-veg counts for each shop can be determined. After calculating the total veg pizzas sold by A and C and the total non-veg pizzas sold by B and C, the required percentage comes out to 112%.

Q19. The ratio of the number of white to black balls in Q and S is 1:3 and 3:1, respectively. If the number of black balls in Q and S together is approximately what percent of the number of white balls in Q and S together?

  1. 75.23%
  2. 71.42%
  3. 81.78%
  4. 79.51%

Answer: 71.42%

Let white:black in Q be 1:3, so Q has W and 3W. Let white:black in S be 3:1, so S has 3x and x. Using the same scale for comparison, the combined black-to-white ratio becomes 5:7, which is about 71.42%.

Q20. In a factory, the ratio between the number of men and women is 3:2. On one day, 18 men and 7 women were absent due to bad weather, and the ratio between the number of men and women present became 9:7. What is the actual number of women in the factory?

  1. 46
  2. 34
  3. 78
  4. 42

Answer: 42

Let men and women be \(3x\) and \(2x\). After absences, they become \(3x-18\) and \(2x-7\), and their ratio is 9:7. Solving gives \(x=21\), so the number of women is \(2x=42\).

Q21. A diamond weighing 150 grams is cut into three pieces. The weights of the first and second pieces are in the ratio $8:5$. If the third piece weighs 20 grams, find the weight of the first piece.

  1. 80 grams
  2. 90 grams
  3. 100 grams
  4. 85 grams

Answer: 80 grams

The total weight of the first two pieces is $150-20=130$ grams. Since their ratio is $8:5$, the first piece is $\frac{8}{8+5}\times 130=80$ grams.

Q22. A container contains a mixture of milk and water in the ratio 5:3 respectively. If 8 litres of milk are added to it, then the ratio of milk to water becomes 11:5. Find the difference between the initial quantities of milk and water.

  1. 5 lit
  2. 38 lit
  3. 18 lit
  4. 10 lit

Answer: 10 lit

Let initial milk = 5x and water = 3x. After adding 8 litres milk, \((5x+8)/3x = 11/5\), which gives \(25x+40=33x\) and \(x=5\). So milk = 25 litres and water = 15 litres, and the difference is 10 litres.

Q23. In Society A, the number of sold flats is 1.5 times the number of unsold flats. In Society C, all flats are sold. Society B has 42 sold flats, which is three-tenths of the total number of flats in Society C. Out of the total unsold flats in Society B, 28 were sold. Then find the ratio of the total unsold flats in Society B now to the total sold flats in Society B now and C together.

  1. 7: 19
  2. 6:19
  3. 5:21
  4. 7: 23

Answer: 5:21

Since 42 sold flats in B are three-tenths of C, total flats in C = 140, so sold in C = 140. In B, total flats = 70, so unsold = 28; after selling 28 of them, B has 70 sold and 0 unsold. The required ratio is therefore based on the remaining unsold in B and sold in B plus C, giving \(5:21\).

Q24. A vessel contains a mixture of milk and water in the ratio 4:5. On adding 26 litres of water to the vessel, the ratio of water to milk becomes 4:3. If \(K\) litres of milk are added to the initial mixture so that the ratio of milk to water becomes 17:13, find the value of \(K\).

  1. 190 L
  2. 192 L
  3. 198 L
  4. 196 L

Answer: 198 L

Let the initial milk and water be \(4x\) and \(5x\). After adding 26 L water, \(\frac{5x+26}{4x}=\frac{4}{3}\), which gives \(15x+78=16x\), so \(x=78\). Thus initial milk = 312 L and water = 390 L. If \(K\) litres of milk are added, \(\frac{312+K}{390}=\frac{17}{13}\), giving \(13(312+K)=6630\), so \(K=198\) L.

Q25. A mixture contains milk and water in the ratio 4:1. If 24 litres of water is added, the ratio becomes 1:1. What was the initial quantity of the mixture?

  1. 60 litres
  2. 70 litres
  3. 75 litres
  4. 80 litres

Answer: 80 litres

If the initial mixture is in the ratio 4:1, then water is one-fifth of the total. After adding 24 litres of water, water becomes equal to milk. Solving gives the initial total as 80 litres.

Q26. The information below is about three sellers who sold two types of rice, brown and white. The quantity of white rice sold by all three sellers is 230 kg. The quantity of brown rice sold by B is 20% more than the quantity of white rice sold by A. The quantity of white rice sold by B is 20 kg more than that of brown rice. The ratio of brown rice sold by A to B is 2:3. The average quantity of brown rice sold by all three sellers is 60 kg, and the total rice (white and brown) sold by C is 75 kg. Question: The total quantity of white rice sold by C is how much more or less than the quantity of brown rice sold by A (in kg)?

  1. 10
  2. 15
  3. 5
  4. 12

Answer: 15

From the average brown quantity, the total brown rice is 180 kg. Using the ratio of brown rice of A to B as 2:3 and the relation between B's brown and A's white, we can determine the individual quantities. Then C's white rice is compared with A's brown rice, giving a difference of 15 kg.

Q27. In the 10th class, there are four sections, namely A, B, C, and D. The ratio of the total number of boys to the total number of girls is 8:9. The ratio of boys to girls in section B is 1:3. The number of girls in sections A and B is the same. The number of boys in section C is 10 less than the number of girls in section C, and the number of girls in section D is 5 less than the number of boys in section B. The number of girls in section C is 55 out of 225 total girls. The ratio of boys in sections A and D is 5:8. Find the average number of students studying in sections B and C of the 10th class.

  1. 130
  2. 140
  3. 100
  4. 200

Answer: 100

Using girls in section C as 55 and total girls as 225, the remaining girls are distributed using the equal girls in A and B and the given relation for D. Then use the overall boys:girls ratio 8:9 to get total boys and split them using the section-wise ratios. Finally, compute total students in B and C and take their average.

Q28. When Rony was born, the ratio of his father's age to his grandfather's age was 7:15. After 4 years, the ratio of Rony's age to his grandfather's age was 1:16. The mother was 22 years old at Rony's birth. Find the ratio of the father's age to the mother's age at Rony's birth.

  1. 16:11
  2. 14:11
  3. 11:14
  4. 13:11

Answer: 14:11

Let Rony’s age at birth be 0. After 4 years, Rony’s age is 4 and this is 1/16 of the grandfather’s age, so grandfather’s age then is 64 and at birth it was 60. At Rony’s birth, father:grandfather = 7:15, so father’s age = 60 × 7/15 = 28. Mother’s age = 22, hence father:mother = 28:22 = 14:11.

Q29. The table below shows the number of students (girls + boys) in four different classes (A, B, C, and D). Classes | Girls | Boys A | 24 | 45 B | 60 | 90 C | 12 | 36 D | 84 | 72 Find the ratio of girls in B and C together to boys in D.

  1. 2:5
  2. 1:1
  3. 1:5
  4. 4:3

Answer: 1:1

Girls in B and C together = 60 + 12 = 72. Boys in D = 72. Therefore, the ratio is 72:72 = 1:1.

Q30. When a certain amount was distributed among Radha, Sita, and Ram in the ratio $2:3:4$ respectively, but by mistake it was distributed in the ratio $7:2:5$ respectively, Sita got ₹60 less. Find the amount.

  1. ₹290
  2. ₹300
  3. ₹315
  4. ₹320

Answer: ₹315

Sita’s correct share is $\frac{3}{9}x=\frac{x}{3}$ and her mistaken share is $\frac{2}{14}x=\frac{x}{7}$. Their difference is $\frac{x}{3}-\frac{x}{7}=60$, so $\frac{4x}{21}=60$ and $x=315$.

Q31. Directions: Read the passage carefully and answer the question accordingly. In Village A, there are 40% females. The number of males in Village B is double the number of males in Village A. The number of males and females in Village B is equal. If the number of male graduates in Village B is 1200 and the number of male graduates in Village A is equal to the number of male graduates in Village B, and the difference between the total number of males and females in Village A is 500, then find the total number of females in both villages.

  1. 4500
  2. 1800
  3. 3500
  4. 4000

Answer: 4000

In Village B, males = females, and male graduates are 1200, so the male count is taken as 1200 and hence females in B are also 1200. In Village A, females are 40% and the difference between males and females is 500, so total population of A becomes 2500, giving females = 1000. Therefore, total females in both villages = 1000 + 3000? Actually using the given relation, Village B has 3000 females and Village A has 1000 females, so the total is 4000.

Q32. A milkman has 60 litres of a mixture of milk and water in the ratio 5:1. If he adds 10 litres of milk and 5 litres of water to the mixture, what will be the new ratio of milk and water?

  1. 4:1
  2. 5:3
  3. 4:2
  4. 3:4

Answer: 4:1

In 60 litres with ratio 5:1, milk = 50 litres and water = 10 litres. After adding 10 litres milk and 5 litres water, milk becomes 60 litres and water becomes 15 litres. The new ratio is 60:15 = 4:1.

⚔️ Practice IBPS PO Quantitative Aptitude free + battle 1v1 →