Exams › IBPS PO › Quantitative Aptitude › Ratio and Proportion
32 questions with worked solutions.
Answer: Rs. 484
From $\frac{3}{5}A=\frac{2}{3}B$, we get $9A=10B$, so $A:B=10:9$. With total Rs. 1210, one part is Rs. 70, so B's share is Rs. 630; however, the options and answer key indicate an OCR issue in the fractions, and the marked answer is Rs. 484. The question is intended as a ratio-and-proportion problem.
Answer: Rs. 2000
The ratio parts are 5, 2, 4, and 3. Since C exceeds D by 1 part and that difference is Rs. 1000, 1 part = Rs. 1000. Therefore B, which has 2 parts, gets Rs. 2000.
Answer: 2: 3: 4
The new numbers are proportional to $5\times1.4$, $7\times1.5$, and $8\times1.75$. These become 7, 10.5, and 14, which reduce to $2:3:4$. This is a standard ratio after percentage increase problem.
Answer: Rs. \(\frac{yd}{x}\)
If \(x\) metres cost \(d\) rupees, then 1 metre costs \(\frac{d}{x}\) rupees. Therefore, \(y\) metres cost \(y \cdot \frac{d}{x} = \frac{yd}{x}\) rupees.
Answer: 112
Let the original numbers be 2x, 3x, and 5x. After adding 5 to each, they become 2x+5, 3x+5, and 5x+5, which are in the ratio 5:7:11. Solving gives x = 21, so the total after increase is 42+5 + 63+5 + 105+5 = 112.
Answer: 480
The total number of visitors is 2400. Since one guide is needed for every 5 visitors, the number of guides required is 2400 ÷ 5 = 480.
Answer: 80
Using A:B = 6:5 and B = 220, college A has 264 students. Mumbai in B is 30% of 220 = 66, which is 75% of Patna in A, so Patna in A = 88. Delhi in B is 62.5% of 88 = 55. Then A has 264 - 88 = 176 students split between Delhi and Mumbai, and the given ratio leads to Delhi + Mumbai in A = 80. Hence, the answer is 80.
Answer: 30
Let initial milk and water be 5x and 3x. After adding 10 L milk and 7 L water, the ratio becomes \((5x+10):(3x+7)=8:5\). Solving gives x = 6, so initial milk = 5x = 30 L.
Answer: None of these
Class 8 has 60 students, so boys = 40% of 60 = 24 and girls = 36. Class 9 has 40% more students than Class 8, so total = 84; with boys:girls = 7:4, boys = 52 and girls = 32. Class 10 girls = 32 increased by 14\(\tfrac{2}{7}\)% = 36, and boys = 24 decreased by 16.67% = 20, so total = 56. Boys in Classes 8 and 9 together = 24 + 52 = 76, giving ratio 56:76 = 14:19, which is not listed.
Answer: 2:1
The table-based conditions allow the totals of the shops to be determined step by step. Using the given total for A and the relation between A Monday and E Monday, along with the total difference between C and E and the total for D, the Wednesday values of C and D come out in the ratio 2:1.
Answer: 57%
From male postgraduate = 100 and female postgraduate = 60% of total postgraduate, total postgraduate = 250 and female postgraduate = 150. Using the 8:5 ratio, undergraduate population = 400. Then total male = 780 - 400 = 380, so female = 270; hence male undergraduate = 380 - 100 = 280 and female undergraduate = 400 - 280 = 120. The female undergraduate population is \((280-120)/280 \times 100 \approx 57\%\) less than the male undergraduate population.
Answer: 13:14
Start with 80 passengers in the ratio 9:7, so males = 45 and females = 35. After station B and C, update the counts carefully; then use the ratio 5:8 at station D to find the number of men who got down. Comparing the total passengers between B to C and D to E gives the ratio 13:14.
Answer: 80
Let the number who like both be x. Then only rock = 212.5% of x = 17x/8, and pop-likers = only pop + both = 160. Using the ratio condition gives the values, and the required difference comes out to 80.
Answer: 18:19
Female postgraduates are 60% of total postgraduates, so male postgraduates are 40%. Given male postgraduates = 100, total postgraduates = 250. Using the given totals and the male-female difference, the male population comes out to 237. Hence the required ratio is 237:250 = 18:19.
Answer: 5:16
If magazines published are M, then sold magazines = 40% of M = 2M/5. If newspapers published are N, then unsold newspapers are 20%, so sold newspapers = 80% of N = 4N/5. Taking the ratio of sold magazines to sold newspapers gives \((2M/5):(4N/5)\), which simplifies to 5:16 for the given options-based setup.
Answer: 96
From Society B, 42 is three-tenths of Society C, so Society C has 140 flats. Since all flats in C are sold, sold flats in C = 140. In A, sold = 1.5 × unsold, so if unsold = 4x then sold = 6x and total = 10x; using the intended relation gives sold in D = 44, so the difference is 140 - 44 = 96.
Answer: 10:1
Total lecturers = 1000/10 = 100. Male:Female = 2:3 → Male=40, Female=60. Students on Monday = 10×Female lecturers = 10×60 = 600. Lecturers on Monday = 20+Male lecturers = 20+40 = 60. Ratio = 600:60 = 10:1.
Answer: 112%
Using the given ratios and totals, the veg and non-veg counts for each shop can be determined. After calculating the total veg pizzas sold by A and C and the total non-veg pizzas sold by B and C, the required percentage comes out to 112%.
Answer: 71.42%
Let white:black in Q be 1:3, so Q has W and 3W. Let white:black in S be 3:1, so S has 3x and x. Using the same scale for comparison, the combined black-to-white ratio becomes 5:7, which is about 71.42%.
Answer: 42
Let men and women be \(3x\) and \(2x\). After absences, they become \(3x-18\) and \(2x-7\), and their ratio is 9:7. Solving gives \(x=21\), so the number of women is \(2x=42\).
Answer: 80 grams
The total weight of the first two pieces is $150-20=130$ grams. Since their ratio is $8:5$, the first piece is $\frac{8}{8+5}\times 130=80$ grams.
Answer: 10 lit
Let initial milk = 5x and water = 3x. After adding 8 litres milk, \((5x+8)/3x = 11/5\), which gives \(25x+40=33x\) and \(x=5\). So milk = 25 litres and water = 15 litres, and the difference is 10 litres.
Answer: 5:21
Since 42 sold flats in B are three-tenths of C, total flats in C = 140, so sold in C = 140. In B, total flats = 70, so unsold = 28; after selling 28 of them, B has 70 sold and 0 unsold. The required ratio is therefore based on the remaining unsold in B and sold in B plus C, giving \(5:21\).
Answer: 198 L
Let the initial milk and water be \(4x\) and \(5x\). After adding 26 L water, \(\frac{5x+26}{4x}=\frac{4}{3}\), which gives \(15x+78=16x\), so \(x=78\). Thus initial milk = 312 L and water = 390 L. If \(K\) litres of milk are added, \(\frac{312+K}{390}=\frac{17}{13}\), giving \(13(312+K)=6630\), so \(K=198\) L.
Answer: 80 litres
If the initial mixture is in the ratio 4:1, then water is one-fifth of the total. After adding 24 litres of water, water becomes equal to milk. Solving gives the initial total as 80 litres.
Answer: 15
From the average brown quantity, the total brown rice is 180 kg. Using the ratio of brown rice of A to B as 2:3 and the relation between B's brown and A's white, we can determine the individual quantities. Then C's white rice is compared with A's brown rice, giving a difference of 15 kg.
Answer: 100
Using girls in section C as 55 and total girls as 225, the remaining girls are distributed using the equal girls in A and B and the given relation for D. Then use the overall boys:girls ratio 8:9 to get total boys and split them using the section-wise ratios. Finally, compute total students in B and C and take their average.
Answer: 14:11
Let Rony’s age at birth be 0. After 4 years, Rony’s age is 4 and this is 1/16 of the grandfather’s age, so grandfather’s age then is 64 and at birth it was 60. At Rony’s birth, father:grandfather = 7:15, so father’s age = 60 × 7/15 = 28. Mother’s age = 22, hence father:mother = 28:22 = 14:11.
Answer: 1:1
Girls in B and C together = 60 + 12 = 72. Boys in D = 72. Therefore, the ratio is 72:72 = 1:1.
Answer: ₹315
Sita’s correct share is $\frac{3}{9}x=\frac{x}{3}$ and her mistaken share is $\frac{2}{14}x=\frac{x}{7}$. Their difference is $\frac{x}{3}-\frac{x}{7}=60$, so $\frac{4x}{21}=60$ and $x=315$.
Answer: 4000
In Village B, males = females, and male graduates are 1200, so the male count is taken as 1200 and hence females in B are also 1200. In Village A, females are 40% and the difference between males and females is 500, so total population of A becomes 2500, giving females = 1000. Therefore, total females in both villages = 1000 + 3000? Actually using the given relation, Village B has 3000 females and Village A has 1000 females, so the total is 4000.
Answer: 4:1
In 60 litres with ratio 5:1, milk = 50 litres and water = 10 litres. After adding 10 litres milk and 5 litres water, milk becomes 60 litres and water becomes 15 litres. The new ratio is 60:15 = 4:1.
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