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A vessel contains a mixture of milk and water in the ratio 4:5. On adding 26 litres of water to the vessel, the ratio of water to milk becomes 4:3. If \(K\) litres of milk are added to the initial mixture so that the ratio of milk to water becomes 17:13, find the value of \(K\).
- 190 L
- 192 L
- 198 L
- 196 L
Correct answer: 198 L
Solution
Let the initial milk and water be \(4x\) and \(5x\). After adding 26 L water, \(\frac{5x+26}{4x}=\frac{4}{3}\), which gives \(15x+78=16x\), so \(x=78\). Thus initial milk = 312 L and water = 390 L. If \(K\) litres of milk are added, \(\frac{312+K}{390}=\frac{17}{13}\), giving \(13(312+K)=6630\), so \(K=198\) L.
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