Exams › IBPS PO › Quantitative Aptitude

If the cost of \(x\) metres of wire is \(d\) rupees, then what is the cost of \(y\) metres of wire at the same rate?

1. Rs. \(\frac{yd}{x}\)
2. Rs. \((xd)\)
3. Rs. \((yd)\)
4. Rs. \(\frac{d}{x}\)

Correct answer: Rs. \(\frac{yd}{x}\)

Solution

If \(x\) metres cost \(d\) rupees, then 1 metre costs \(\frac{d}{x}\) rupees. Therefore, \(y\) metres cost \(y \cdot \frac{d}{x} = \frac{yd}{x}\) rupees.

Related IBPS PO Quantitative Aptitude questions

• A and B together have Rs. 1210. If $\frac{3}{5}$ of A's amount is equal to $\frac{2}{3}$ of B's amount, how much amount does B have?
• A sum of money is to be distributed among A, B, C, and D in the proportion $5:2:4:3$. If C gets Rs. 1000 more than D, what is B's share?
• Seats for Mathematics, Physics, and Biology in a school are in the ratio $5:7:8$. There is a proposal to increase these seats by 40%, 50%, and 75% respectively. What will be the ratio of the increased seats?
• Students in three hostels are in the ratio 2:3:5. If each hostel has 5 more students than before, the new ratio becomes 5:7:11. What is the total number of students after the increase?
• Total visitors over all four days = 500 + 400 + 800 + 700 = 2400. If one guide is required for every 5 visitors, how many guides are required in total?
• Passage: There are 220 students in college B. Students are from Patna, Delhi, and Mumbai. The ratio of students in college A to college B is 6:5. Mumbai students in B are 30% of B. Mumbai students in B are 75% of Patna students in A. Delhi students in B are 62.5% of Patna students in A. The ratio of Patna students in B to Mumbai students in A is 9:10. Question: What is the total number of students in college A from Delhi and Mumbai?

⚔️ Practice IBPS PO Quantitative Aptitude free + battle 1v1 →