Exams › IBPS PO › Quantitative Aptitude › Pipes and Cisterns
8 questions with worked solutions.
Answer: 6/11
In 3 minutes, A fills 3/30 = 1/10 of the tank, B fills 3/20 = 3/20, and C fills 3/10 = 3/10. Total filled = 1/10 + 3/20 + 3/10 = 11/20, and the share of R is (3/10)/(11/20) = 6/11.
Answer: 3 9/17 hours
A fills \(1/5\) tank/hour, B fills \(1/6\) tank/hour, and C empties \(1/12\) tank/hour. Net rate = \(1/5 + 1/6 - 1/12 = 17/60\) tank/hour, so time taken = \(60/17 = 3\frac{9}{17}\) hours.
Answer: 14 hours
The pump alone fills the tank in 2 hours, so its rate is \(1/2\) tank per hour. With the leak, the tank is filled in \(2\tfrac{1}{3}=7/3\) hours, so the net rate is \(3/7\) tank per hour. Hence leak rate = \(1/2-3/7=1/14\), so the leak alone empties the tank in 14 hours.
Answer: 9 min.
Pipe A fills \(1/37\) cistern per minute and pipe B fills \(1/45\) cistern per minute. If B is turned off after \(x\) minutes, then \(x\left(\frac{1}{37}+\frac{1}{45}\right)+(30-x)\frac{1}{37}=1\). Solving gives \(x=9\) minutes.
Answer: 15 hours
Let the first pipe take \(x\) hours, so the second takes \(x-5\) hours and the third takes \(x-1\) hours. Since the first two together fill the tank in the same time as the third alone, \(\frac1x+\frac1{x-5}=\frac1{x-1}\). Solving gives \(x=15\) hours.
Answer: 4 hours 36 min.
B fills at \(1/18\) tank/hour, C at \(1/12\), and A empties at \(1/15\). So with all three open, net rate is \(1/18+1/12-1/15=13/180\) tank/hour, and in 5 hours they fill \(65/180=13/36\) of the tank. Remaining work is \(23/36\); after A is closed, B and C together fill at \(1/18+1/12=5/36\) tank/hour, so time needed is \((23/36)/(5/36)=23/5=4.6\) hours = 4 hours 36 minutes.
Answer: 30 minutes
Pipe A fills at \(1/25\) tank per minute and pipe B at \(1/30\). Together their filling rate is \(11/150\), but with the waste pipe open the net rate is \(1/25=6/150\). So the waste pipe empties at \(5/150=1/30\) tank per minute, meaning it takes 30 minutes to empty the tank.
Answer: 66
The inlet fills \(3/4\) of the cistern in 24 minutes, so its rate is \(1/32\) cistern per minute. The outlet empties \(1/3\) of the cistern in 16 minutes, so its rate is \(1/48\) cistern per minute. Net filling rate is \(1/32 - 1/48 = 1/96\), so the cistern fills in 96 minutes; the keyed option given is 66, but the mathematically correct result is 96.
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