Exams › IBPS PO › Quantitative Aptitude › Coordinate Geometry
9 questions with worked solutions.
Answer: \u221a340 m
Let H be at (0,0). Then C is at (0,12), so G is at (-8,12). Also, I is 6 m east of H, so I is at (6,0). The distance between I and G is \(\sqrt{(6-(-8))^2+(0-12)^2}=\sqrt{14^2+12^2}=\sqrt{340}\).
Answer: √340 m
By assigning coordinates from the given relations, the positions of N and K can be determined exactly. The distance between them comes out to \(\sqrt{340}\) m using the coordinate distance formula.
Answer: √89 Km
Take M as (0,0). Then N is at (0,7). Moving right from north means east, so O is at (5,7), and then left from east means north, so P is at (5,15). The distance between P(5,15) and N(0,7) is \(\sqrt{(5-0)^2+(15-7)^2}=\sqrt{25+64}=\sqrt{89}\).
Answer: \(\sqrt{34}\) m
Take B as \((0,0)\). Then F is at \((5,0)\), and G is at \((5,3)\). The shortest distance from B to G is \(\sqrt{5^2+3^2}=\sqrt{34}\) m.
Answer: 12 m
Taking O as the origin, N is at (-8,0). P is at (0,-4), so Q is at (4,-4), and A is 4 m north of Q, i.e. at (4,0). The distance between (-8,0) and (4,0) is 12 m.
Answer: 4 km
Take P as (0,0). Then Q = (8,0), R = (8,-4), S = (4,-4), T = (4,-10), and U, the midpoint of S and T, is (4,-7). Also W = (0,-7) since it is 7 km south of P. Therefore, the distance between W and U is 4 km.
Answer: 15.02 km
By tracking the path on a coordinate plane, the positions of B, G, A, and J can be determined exactly. Then BG and AJ are found using the distance formula. The difference comes out to 15.02 km.
Answer: 18 m
By assigning coordinates, the relative positions of all points can be determined. From the given constraints, point G ends up 1 m north of point F and aligned horizontally so that the straight-line distance between G and F is 18 m.
Answer: 2 km
The path can be reduced by converting each move into coordinate shifts. After all movements, the net displacement from the house is 2 km, so the straight-line distance is 2 km.
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