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IBPS PO Quantitative Aptitude: Coordinate Geometry questions with solutions

9 questions with worked solutions.

Questions

Q1. Point G is 8 m west of point C, which is 12 m north of point H. Point I is 6 m east of point H. Point K is 15 m west of point D, which is 18 m south of point G. Point E is 10 m west of point B and 27 m north of point K. Point F is 5 m north of point B. Point F is 20 m east of point A. What is the shortest distance between point I and point G?

  1. 18 m
  2. \u221a340 m
  3. \u221a288 m
  4. 12 m

Answer: \u221a340 m

Let H be at (0,0). Then C is at (0,12), so G is at (-8,12). Also, I is 6 m east of H, so I is at (6,0). The distance between I and G is \(\sqrt{(6-(-8))^2+(0-12)^2}=\sqrt{14^2+12^2}=\sqrt{340}\).

Q2. Directions for Questions 48–50: Study the following information and answer the questions given below. Point A is 3 m east of point B. Point D is 4 m north of C. Point K is 7 m west of J. Point D is 4 m south of A. Point L is 4 m south of G, who is 6 m west of F. Point E is 5 m east of C and point B is 5 m north of F. Point M is 5 m south of E, who is 4 m west of N. Point K is 3 m north of Q. Point I is 4 m east of A. Point J is 6 m north of I. Q. (48) What is the shortest distance between point N and point K?

  1. 340 m
  2. √340 m
  3. 75 m
  4. √341 m

Answer: √340 m

By assigning coordinates from the given relations, the positions of N and K can be determined exactly. The distance between them comes out to \(\sqrt{340}\) m using the coordinate distance formula.

Q3. Study the following information carefully and answer the question given below: Veer started walking from point M towards north for 7 km to reach point N. Then, he took a right turn and walked 5 km to reach point O. After that, he took a left turn and walked 8 km to reach point P. Then, he turned towards west and walked 9 km to reach point Q. From point Q, he walked 6 km south to reach point R. What is the shortest distance between point P and point N?

  1. 89 Km
  2. √89 Km
  3. √88 Km
  4. 18 Km

Answer: √89 Km

Take M as (0,0). Then N is at (0,7). Moving right from north means east, so O is at (5,7), and then left from east means north, so P is at (5,15). The distance between P(5,15) and N(0,7) is \(\sqrt{(5-0)^2+(15-7)^2}=\sqrt{25+64}=\sqrt{89}\).

Q4. Point A is 10 m west of point B. Point B is 7 m south of point C. Point D is 6 m west of point C. Point E is 7 m south of point D. Point F is 5 m east of point B. Point G is 3 m north of point F. What is the shortest distance between point B and point G?

  1. 34 m
  2. 32 m
  3. \(\sqrt{35}\) m
  4. \(\sqrt{34}\) m

Answer: \(\sqrt{34}\) m

Take B as \((0,0)\). Then F is at \((5,0)\), and G is at \((5,3)\). The shortest distance from B to G is \(\sqrt{5^2+3^2}=\sqrt{34}\) m.

Q5. Study the following information carefully and answer the question given below: Point N is 8 m to the west of point O. Point P is 4 m to the south of point O. Point Q is 4 m to the east of point P. Point R is 6 m to the north of point Q. Point S is 8 m to the west of point R. Point T is 2 m to the south of point S. If point A is 4 m to the north of point Q, then what is the minimum distance between N and A?

  1. 16 m
  2. 8 m
  3. 12 m
  4. 10 m

Answer: 12 m

Taking O as the origin, N is at (-8,0). P is at (0,-4), so Q is at (4,-4), and A is 4 m north of Q, i.e. at (4,0). The distance between (-8,0) and (4,0) is 12 m.

Q6. There are eight bus stops P, Q, R, S, T, U, V and W. Q is 8 km east of P. S is 4 km west of R. W is 7 km south of P. R is 4 km south of Q. V is in the middle of P and Q. T is 6 km south of S. U is in the middle of S and T. What is the distance between W and U?

  1. 8 km
  2. 6 km
  3. 4 km
  4. 3 km

Answer: 4 km

Take P as (0,0). Then Q = (8,0), R = (8,-4), S = (4,-4), T = (4,-10), and U, the midpoint of S and T, is (4,-7). Also W = (0,-7) since it is 7 km south of P. Therefore, the distance between W and U is 4 km.

Q7. A person starts from place A and goes up to place J through B, C, D, E, F, G, H, and I in the same order as mentioned. From A, he travels 8 km towards north to reach B, then he takes a right turn and travels 7 km to reach C. From C, he travels 12 km towards the south to reach D, then he turns left and travels 13 km to reach E, then he again turns left and travels 6 km to reach F. From F, he travels 10 km towards west to reach G, then he takes a left turn and travels 16 km to reach H, then he takes a left turn, travels 16 km to reach I, then again turns left and travels 8 km to reach J. How much less is BG than AJ?

  1. 16 km
  2. 15.6 km
  3. 15.02 km
  4. 16.8 km

Answer: 15.02 km

By tracking the path on a coordinate plane, the positions of B, G, A, and J can be determined exactly. Then BG and AJ are found using the distance formula. The difference comes out to 15.02 km.

Q8. Point A is 11 m to the west of point B. Point C is 8 m to the south of point B. Point C is 1 m to the west of point J. Point J is 12 m to the south of point H. Point D is 11 m to the east of point J. Point E is 6 m to the south of point D. Point F is 17 m to the west of point E. Point G is to the north of point F and to the west of point H. What is the shortest distance between point G and point F?

  1. 17 m
  2. 18 m
  3. 19 m
  4. 21 m

Answer: 18 m

By assigning coordinates, the relative positions of all points can be determined. From the given constraints, point G ends up 1 m north of point F and aligned horizontally so that the straight-line distance between G and F is 18 m.

Q9. Prithvi starts walking from his home in the south direction and walks 7 km to reach point A. Then he takes a right turn and walks 5 km to reach point B. From point B, he turns 90 degrees to his left and walks 8 km to reach point C. From point C again, he turns 90 degrees to his left and walks 10 km to reach point D. Then he takes a left turn and walks 17 km in the north direction to reach point E. Finally, he makes a 90-degree left turn and walks 5 km to reach point F. Question: What is the distance between Prithvi's house and the final point?

  1. 3 km
  2. 5 km
  3. 1 km
  4. 2 km

Answer: 2 km

The path can be reduced by converting each move into coordinate shifts. After all movements, the net displacement from the house is 2 km, so the straight-line distance is 2 km.

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