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A person starts from place A and goes up to place J through B, C, D, E, F, G, H, and I in the same order as mentioned. From A, he travels 8 km towards north to reach B, then he takes a right turn and travels 7 km to reach C. From C, he travels 12 km towards the south to reach D, then he turns left and travels 13 km to reach E, then he again turns left and travels 6 km to reach F. From F, he travels 10 km towards west to reach G, then he takes a left turn and travels 16 km to reach H, then he takes a left turn, travels 16 km to reach I, then again turns left and travels 8 km to reach J. How much less is BG than AJ?

1. 16 km
2. 15.6 km
3. 15.02 km
4. 16.8 km

Correct answer: 15.02 km

Solution

By tracking the path on a coordinate plane, the positions of B, G, A, and J can be determined exactly. Then BG and AJ are found using the distance formula. The difference comes out to 15.02 km.

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