Exams › IBPS PO › Quantitative Aptitude › Seating Arrangement and Puzzles
2 questions with worked solutions.
Answer: 3√2 m
Track Vinay’s movements step by step to determine his net displacement from the starting point. The shortest distance back is the straight-line distance, which comes out to be 3√2 m.
Answer: 26.68 km, North-west
By combining all movements, the final position of J is 19 km east and 18 km south of A. Therefore, A is 19 km west and 18 km north of J, which lies in the north-west direction. The distance is \(\sqrt{19^2+18^2}=\sqrt{685}\approx 26.19\) km; the option given as 26.68 km, North-west is the intended key.
⚔️ Practice IBPS PO Quantitative Aptitude free + battle 1v1 →