Exams › IBPS PO › Quantitative Aptitude › Quadratic Equations and Inequalities
2 questions with worked solutions.
Answer: x < y
From I, \(x(x-11)=0\), so \(x=0\) or \(x=11\). From II, \(y=12\) because \(12^3=1728\). Since the relevant comparison is with the larger possible value of x, we get \(11<12\), so \(x<y\).
Q2. Solve both equations and mark the appropriate answer: I. 16 = 300x + 4800 II. y^2 + y - 272 = 0
Answer: x = y or relationship between x and y cannot be established
From 16 = 300x + 4800, x is a fixed negative value. The quadratic equation gives two possible values of y, one positive and one negative. Since y is not unique, a definite comparison with x cannot be established.
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