Solve both equations and mark the appropriate answer: I. 16 = 300x + 4800 II. y^2 + y - 272 = 0

x = y or relationship between x and y cannot be established
x < y
x b7 y
x d7 y

Correct answer: x = y or relationship between x and y cannot be established

Solution

From 16 = 300x + 4800, x is a fixed negative value. The quadratic equation gives two possible values of y, one positive and one negative. Since y is not unique, a definite comparison with x cannot be established.

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