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ExamsIBPS POQuantitative Aptitude

In a bag, there are 3 magenta balls, 5 green balls, and 7 blue balls. Two balls are drawn one by one without replacement. If the first ball drawn is magenta, then 8 more magenta balls are added to the bag. Find the probability that both balls drawn are magenta.

  1. 1/35
  2. 2/11
  3. 1/11
  4. 1/23

Correct answer: 1/11

Solution

The probability of drawing a magenta ball first is \(3/15 = 1/5\). After that ball is removed and 8 magenta balls are added, the bag has 10 magenta balls out of 22 total balls, so the second magenta probability is \(10/22 = 5/11\). Multiplying gives \(1/5 \times 5/11 = 1/11\).

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