In the given question, two equations numbered I and II are given. Solve both equations and mark the appropriate answer. I. \(x^2 - 11x = 0\) II. \(y^3 = 1728\)

x > y
x < y
x ≥ y
x ≤ y

Correct answer: x < y

Solution

From I, \(x(x-11)=0\), so \(x=0\) or \(x=11\). From II, \(y=12\) because \(12^3=1728\). Since the relevant comparison is with the larger possible value of x, we get \(11<12\), so \(x<y\).

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