Question 1

What is formed when an excess amount of sodium hydroxide is added to a solution of stannous chloride?

Accepted Answer

Na2SnO2. SnCl2 first gives Sn(OH)2, which is amphoteric and dissolves in excess NaOH to form sodium stannite, Na2SnO2 (i.e. Na2[Sn(OH)4]). The product is Na2SnO2, not SnO2 + H2O, so option index 2 is correct.

Question 2

Which of the following substituted silanes can form a cross-linked silicone polymer upon undergoing hydrolysis?

Accepted Answer

RSiCl3. The correct option is RSiCl3 because it has three reactive chlorine atoms that can undergo hydrolysis to form a cross-linked silicone polymer, which is a characteristic of this type of silane.

Question 3

Which pairs of reactants most effectively demonstrate the dual acidic and basic behavior of Al2O3.xH2O?

Accepted Answer

Pairs 3 and 4. Pairs 3 and 4 are correct because they demonstrate the amphoteric behavior of Al2O3.xH2O, reacting with both acids and bases to show its dual acidic and basic nature.

Question 4

Among the following oxides, which one acts as the most potent oxidizing agent?

Accepted Answer

Lead dioxide (PbO2). Down group 14 the +2 state becomes more stable (inert-pair effect), so the +4 oxide of lead is the strongest oxidizer, readily reduced to Pb(II). PbO2 is the most potent oxidizing agent; GeO2 (stored) is very stable. Correct option: PbO2.

Question 5

Among the following compounds, which one acts as the most powerful reducing agent?

Accepted Answer

Tin(II) chloride (SnCl2). Tin(II) chloride is the most powerful reducing agent because it can easily donate electrons to other substances, reducing them and itself getting oxidized in the process.

Question 6

Which xenon-oxygen compound cannot be produced through the hydrolysis of xenon fluorides?

Accepted Answer

XeO₄. XeO₄ cannot be produced through the hydrolysis of xenon fluorides due to the instability and reactivity of XeO₄, which makes its formation through this method unfeasible.

Question 7

When ICl2 gas is bubbled through an aqueous KI solution containing CCl4 and the mixture is agitated, what is observed?

Accepted Answer

The bottom layer turns violet. The bottom layer turns violet when ICl₂ gas is bubbled through an aqueous KI solution containing CCl₄ because the reaction between ICl₂ and KI in the presence of CCl₄ leads to the formation of a violet-colored product that settles at the bottom.

Question 8

Why is concentrated H2SO4 not a good choice for reacting with solid KI to produce HI?

Accepted Answer

Iodide ions are converted into iodine molecules.. Concentrated H₂SO₄ is not a good choice for reacting with solid KI to produce HI because the strong oxidizing properties of H₂SO₄ cause the iodide ions to be converted into iodine molecules, rather than forming the desired HI product.

Question 9

Aluminium oxide demonstrates amphoteric behavior as it interacts with both acids and bases to produce salt and water. In the reaction Al2O3 + H2O + 2NaOH → NaAlO2 + H2O, it reacts with a base, while in the reaction Al2O3 + xH2O + HCl → AlCl3 + H2O, it reacts with an acid. What type of acid

Accepted Answer

Highly acidic substance. HCl is a highly acidic substance as it completely dissociates in water to produce H+ ions, which is characteristic of strong acids

Question 10

In the reaction of diborane with water, ammonia at low temperature, and ammonia at high temperature, what is the nature of H3BO3 formed as a product?

Accepted Answer

Mild acid. The correct answer is that H3BO3 is a mild acid because it partially dissociates in water to release a few hydrogen ions, but not completely, resulting in a weak acidic nature.

Question 11

Which of the following is classified as a strong base?

Accepted Answer

Calcium oxide. Calcium oxide is a strong base as it completely dissociates in water to produce hydroxide ions, resulting in a high pH value.

Question 12

Concentrated nitric acid, upon long standing, turns yellow-brown due to the formation of -

Accepted Answer

NO2. Concentrated nitric acid decomposes over time, forming NO₂ gas, which gives the yellow-brown color.

Question 13

What is the compound obtained when white phosphorus reacts with thionyl chloride?

Accepted Answer

Phosphorus trichloride. The correct answer is Phosphorus trichloride because white phosphorus reacts with thionyl chloride to produce phosphorus trichloride, sulfur dioxide, and sulfur dichloride.

Question 14

What is the sequence of oxidation states of phosphorus in the compounds H₃PO₂, H₃PO₃, H₃PO₄, and H₄P₂O₆?

Accepted Answer

H₃PO₄ > H₄P₂O₆ > H₃PO₃ > H₃PO₂. The sequence of oxidation states of phosphorus in the given compounds can be determined by calculating the oxidation state of phosphorus in each compound, considering the oxidation states of hydrogen and oxygen, and then arranging them in order of decreasing oxidation state.

Question 15

When potassium chlorate (KClO3) is heated with a small amount of manganese dioxide (MnO2) as a catalyst, a gas W is released. If W is allowed to react with white phosphorus, it produces a compound X. Upon treating X with concentrated nitric acid (HNO3), two products Y and Z are formed. Wha

Accepted Answer

Dinitrogen pentoxide (N2O5) and metaphosphoric acid (HPO3). Potassium chlorate heated with manganese dioxide produces oxygen gas, which reacts with white phosphorus to form tetraphosphorus decaoxide. This compound then reacts with concentrated nitric acid to produce dinitrogen pentoxide and metaphosphoric acid.

Question 16

When potassium chlorate is heated with a small amount of manganese dioxide as a catalyst, a gas W is produced. When W is in excess, it reacts with white phosphorus to form compound X. Upon treating X with concentrated nitric acid, compounds Y and Z are formed. What are W and X, respectivel

Accepted Answer

Oxygen and tetraphosphorus decaoxide. The gas W produced by heating potassium chlorate with manganese dioxide is oxygen, which then reacts with white phosphorus to form tetraphosphorus decaoxide, denoted as X.

Question 17

Which of the following pairs of reactions produces the same gaseous product?

Accepted Answer

[(NH4)2Cr2O7 heated strongly] and (NH4NO2 heated strongly). Both (NH4)2Cr2O7 and NH4NO2 decompose on heating to yield N2 gas (along with water and solid Cr2O3 in the first case). No other pair in the options produces the same single gas from both reactions.

Question 18

Among the four statements below about chemical reactions involving p-block and other inorganic compounds, identify the ONE that is INCORRECT: (P) The stability of dihalides follows the order: SiX2 < GeX2 < SnX2 < PbX2 (Q) The reaction 2NH3 + H2O + CO2 -> (NH4)2CO3 correctly represents ammo

Accepted Answer

(R) When Na2CO3*10H2O is heated below 373 K, it decomposes into Na2O, CO2, and 10H2O. Heating Na2CO3*10H2O below 373 K causes it to lose water of crystallisation (efflorescence), giving anhydrous Na2CO3 (or monohydrate), NOT Na2O and CO2; decomposition into Na2O requires very high temperatures. Statement R is therefore incorrect.

Question 19

A certain compound X, when heated, produces a gas Y. The same gas Y is also produced when barium nitrate reacts with zinc in aqueous KOH solution. Identify compound X.

Accepted Answer

Compound X is (NH4)2Cr2O7. (NH4)2Cr2O7 thermally decomposes in a spectacular 'volcano' reaction to give N2 gas, Cr2O3, and water. Reduction of nitrate by Zn in alkaline medium can also produce N2, linking Y = N2 to compound X = (NH4)2Cr2O7.

Question 20

Count the number of specific linkages in the following species and find their sum: - m1 = number of S-S bonds in S3O9 (trithionate-type species) - m2 = number of P-P bonds in (HPO3)3 (cyclic trimetaphosphate) - m3 = number of S-S bonds in S2O8²- (peroxodisulfate ion) - m4 = number of O-O b

Accepted Answer

2. Only trithionate contributes S-S bonds (m1=2); the other species either lack the asked bond type entirely: metaphosphate has no P-P (m2=0), peroxodisulfate has no S-S (m3=0), and dithionate has no O-O (m4=0). Sum = 2.

Question 21

A white waxy solid P reacts with 3 mol NaOH and 3 mol H2O to form two products Q and R. When Q is burned in oxygen (with heating), it gives product S. Given that Q is a colourless gas with a characteristic rotten-fish smell, which of the following statements about P, Q, R, and S is CORRECT

Accepted Answer

The anionic part of R contains zero acidic hydrogen atoms. Q is PH3 (phosphine — colourless gas, rotten fish odour). P is P4 (white phosphorus, waxy solid). R is NaH2PO2 (sodium hypophosphite). The anion H2PO2⁻ has both H atoms on P (P-H bonds), giving zero acidic (O-H) hydrogens in the anion.

Question 22

A white, colourless crystalline solid is strongly heated. A sharp crackling sound is produced, reddish-brown fumes are evolved, and the solid residue left behind is yellowish-brown. When a glowing wooden splint is introduced into the evolved fumes, it bursts into flame. The fumes are compo

Accepted Answer

NO2 and O2. Lead nitrate is a white crystalline solid that decomposes with a crackling sound (decrepitation) on heating, giving reddish-brown NO2 gas and O2 gas (which relights a glowing splint), leaving behind yellowish-brown PbO as residue.

Question 23

From the list of reagents — AgNO3, BaCl2, Pb(OAc)2, HgCl2, CuSO4, SbCl3 — how many will produce a black precipitate of the metal sulphide when treated with H2S?

Accepted Answer

4. AgNO3 gives Ag2S (black), Pb(OAc)2 gives PbS (black), HgCl2 gives HgS (black), and CuSO4 gives CuS (black) — four black precipitates. BaCl2 gives no precipitate (BaS is soluble) and SbCl3 gives Sb2S3 which is orange.

Question 24

Consider the following two statements about ionization enthalpy trends in Group 13: Statement I: The decrease in first ionization enthalpy going from B to Al is much larger than the decrease going from Al to Ga. Statement II: The 3d orbitals in gallium (Ga) are completely filled. Which of

Accepted Answer

Both Statement I and Statement II are correct.. Statement I is correct: IE1 drops sharply from B (~800 kJ/mol) to Al (~577 kJ/mol) but barely changes from Al to Ga (~579 kJ/mol). Statement II is correct: Ga has a completely filled 3d¹⁰ shell. The d electrons shield poorly, increasing effective nuclear charge in Ga and explaining why IE does not drop further from Al to Ga.

Question 25

Which of the following statements about xenon tetrafluoride (XeF4) is/are correct?

Accepted Answer

All of the above. Xe in XeF4 uses sp3d2 hybridisation (6 electron pairs: 4 bonding + 2 lone pairs). The molecule is square planar. The two lone pairs are in axial positions, mutually cancelling, so the net dipole moment is zero. XeF4 is therefore non-polar. All three individual statements are correct.

Question 26

A white-coloured sodium salt is dissolved in water. The resulting solution shows neutral behaviour toward litmus. When aqueous silver nitrate is added to this solution, a white precipitate forms that is insoluble in dilute nitric acid. Identify the anion present in the salt.

Accepted Answer

Cl-. Sodium chloride solution is neutral to litmus. AgCl is a white precipitate that does not dissolve in dilute HNO3 because HNO3 cannot shift the AgCl equilibrium (unlike Ag2CO3 or Ag2S which react with acid). The other anions either give alkaline solutions (CO3²-, S²-) or give precipitates soluble in acid (SO3²-).

Question 27

Which of the following species does NOT exist in reality?

Accepted Answer

Both ClI3 and XeH4. XeH4 does not exist because hydrogen is not electronegative enough to oxidize xenon, and no Xe-H compounds are known. ClI3 does not exist because chlorine, being smaller and more electronegative than iodine, cannot act as the central atom bonded to three bulky iodine atoms. BiF5 does exist as bismuth(V) fluoride. Hence both A and B are non-existent.

Question 28

Borate ion (BO3³-) is treated with concentrated H2SO4 and heated, producing compound P which gives white fumes. In a separate experiment, the same borate ion is heated with concentrated H2SO4 in the presence of ethanol (C2H5OH), producing compound Q whose vapours can be ignited with a gree

Accepted Answer

P = H3BO3, Q = (C2H5O)3B. When BO3³- reacts with concentrated H2SO4, boric acid (H3BO3) is liberated; it sublimes as white fumes. When ethanol is also present, the H3BO3 formed immediately esterifies with ethanol to give triethyl borate (C2H5O)3B, which burns with a characteristic green-bordered flame — the standard test for boron compounds.

Question 29

Which of the following statements about calcium phosphite is INCORRECT?

Accepted Answer

All O–P–O bond angles in it are equal. Calcium phosphite is Ca(HPO3) or Ca3(HPO3)3 depending on convention; the phosphite ion HPO3²- has the structure where P is bonded to one H, one =O (double bond or dative), and two O⁻ groups. Since one substituent is H (not O), the geometry around P is not symmetric and all O–P–O bond angles are NOT equal. Option D is therefore incorrect. The formula Ca3(PO3)2 (option A) represents the salt of phosphite PO3³-, which is less common, but the oxidation state of P is indeed +3 (option C is correct), and the P–H bond (option B) is correct for H-phosphonate type

Question 30

Which among the following are ionic carbides?

Accepted Answer

CaC2. CaC2 (calcium carbide) and Be2C (beryllium carbide) are ionic carbides. Al4C3 is also ionic (methanide type). SiC is a covalent carbide. Among the options, CaC2, Al4C3, and Be2C are ionic carbides, while SiC is not.

Question 31

Which of the following chemical reactions is correct?

Accepted Answer

SO3²- + 2H⁺ -> SO2 (colourless gas) + H2O. Option C (SO3²- + 2H⁺ -> SO2 + H2O) is a correctly balanced reaction: sulphite ions reacting with acid produce sulphur dioxide gas (colourless, pungent) and water. Option A's second step is unbalanced and incorrect. Option B is missing electrons/charges — the actual reaction of NO3⁻ with H2SO4 does not produce O2. Option D's product I3⁻ is wrong (should be I2).

Question 32

Which of the following anions produces a reddish-brown gas when treated with concentrated H2SO4?

Accepted Answer

Br-. When Br- ions react with concentrated H2SO4, the acid first forms HBr, which is then partially oxidised by the concentrated H2SO4 to give Br2 (reddish-brown gas) along with SO2. NO3- gives colourless NO2 (actually brown NO2), SO3²- gives SO2 (colourless pungent), and I- gives violet I2 vapour.

Question 33

Which of the following industrial process-reaction pairs is correctly described?

Accepted Answer

Ostwald process: 4NH3 + 5O2 --[Pt/Rh, 500 K, 9 bar]--> 4NO + 6H2O. Option A (Ostwald process) is correctly stated. Option B's stoichiometry in original was written as SO2 + 1/2 O2 which is correct but the option as written with coefficient check: 2SO2 + O2 -> 2SO3 is also correct. Option C is correct for Deacon's. Option D has an error: Mo is not used in Haber's process. Thus A, B, C are correct while D is wrong.

Question 34

Three statements about halogens are given below: (P) The bond length order is F2 < Cl2 < Br2 < I2. (Q) The oxidising power order is F2 > Cl2 > Br2 > I2. (R) The correct order of bond dissociation energy is Cl2 > Br2 > F2 > I2. Which of the following is correct?

Accepted Answer

P and Q are correct. Bond length increases down the group (P correct). Oxidising power decreases down the group (Q correct). Standard BDE values: F2~159, Cl2~242, Br2~193, I2~151 kJ/mol, giving Cl2>Br2>F2>I2, so R is also correct. Hence all three are correct.

Question 35

On heating, how many of the following compounds produce BOTH an acidic product AND a basic product simultaneously? LiNO3, CaCO3, NH4NO3, FeSO4, Mg(OH)2

Accepted Answer

1. LiNO3 -> Li2O (basic) + NO2 (acidic) + O2: gives both acidic and basic products. CaCO3 -> CaO (basic) + CO2 (acidic): gives both. NH4NO3 -> N2O + H2O: only neutral products. FeSO4 -> Fe2O3 + SO2 + SO3: gives acidic oxides and basic oxide. Mg(OH)2 -> MgO + H2O: only basic oxide + neutral. Careful count: LiNO3, CaCO3, and FeSO4 give both acidic and basic products = 3.

Question 36

In the mineral beryl, Be3Al2Si6O18, how many oxygen atoms are shared by each SiO4 tetrahedral unit?

Accepted Answer

2. Beryl belongs to the cyclosilicate class with Si6O18¹²- ring anion. In this six-membered ring structure, each SiO4 tetrahedron shares two of its four oxygen atoms with neighboring tetrahedra (the two bridging oxygens), while two oxygens remain unshared (terminal). Hence, each SiO4 unit shares 2 oxygen atoms.

Question 37

How many nitrate groups (NO3-) are present in one molecule of basic beryllium nitrate?

Accepted Answer

3. Basic beryllium nitrate is typically represented as Be4O(NO3)6, which is a tetranuclear cluster analogous to basic beryllium acetate. This formula contains 6 nitrate groups per molecule. However, if the question refers to a simpler formula unit, it could have 3 nitrate groups. The most commonly cited structure in Indian textbooks is Be4O(NO3)6 with 6 NO3.

Question 38

Consider the following hydrolysis reactions: AsCl3 + excess H2O gives an oxyacid and a hydroacid. PCl3 + excess H2O gives an oxyacid and a hydroacid. PCl5 + 1 mole H2O gives an unknown product Z and HCl. The ratio of the number of pi bonds to the number of sigma bonds in compound Z is:

Accepted Answer

1:5. PCl5 + H2O (1 mole) gives POCl3 (Z) + 2HCl. In POCl3: there is 1 P=O double bond (1 pi bond + 1 sigma bond) and 3 P-Cl single bonds (3 sigma bonds), plus the sigma component of P=O. Total sigma bonds = 1 (P=O sigma) + 3 (P-Cl) = 4, plus the coordinate/dative bond can be counted as 1 sigma = total 4 sigma bonds from P centre. Actually counting: P=O has 1 sigma + 1 pi; 3 x P-Cl each has 1 sigma. Total sigma = 4, total pi = 1. Ratio pi:sigma = 1:4. However treating the P=O as a coordinate bond (dative bond, counts as sigma), ratio is 0:4 = not listed. Using the standard Lewis structure with

Question 39

Consider the following statements about carbides and choose the correct one(s): (I) CaC2 is an ionic carbide that produces acetylene on hydrolysis. (II) Al4C3 is an ionic carbide that produces methane on hydrolysis. (III) Be2C is an ionic carbide that produces methane on hydrolysis. (IV) S

Accepted Answer

(C) I, II, III and IV. CaC2 (calcium carbide) is an ionic acetylide: CaC2 + 2H2O -> Ca(OH)2 + C2H2 (acetylene). Al4C3 (aluminum carbide) is an ionic methanide: Al4C3 + 12H2O -> 4Al(OH)3 + 3CH4. Be2C (beryllium carbide) is an ionic methanide: Be2C + 4H2O -> 2Be(OH)2 + CH4. SiC (silicon carbide, carborundum) is a giant covalent structure with a very high melting point (~2730 deg C). All four statements are correct.

Question 40

Which of the following reactions produce NO2 gas as the primary nitrogen oxide product?

Accepted Answer

Zn reacting with concentrated HNO3. Concentrated HNO3 reacts with metals to give NO2. Zn with concentrated HNO3 gives NO2. Dilute HNO3 with most metals (Cu, Zn, Sn) gives NO, not NO2. Cu with dilute HNO3 produces NO (not NO2). So only Zn + conc. HNO3 produces NO2 among the given options.

Question 41

How many p-pi to p-pi bonds are present in XeO4?

Accepted Answer

4. XeO4 has tetrahedral geometry (4 double bonds, Xe oxidation state +8). Each Xe=O bond consists of one sigma bond and one pi bond formed by overlap of oxygen p orbital with xenon d (or p) orbital — these are p-pi to d-pi bonds. However in the context of p-pi to p-pi bonds, XeO4 is often cited to have 4 such bonds (one per Xe=O bond), using the oxygen lone pair p orbitals donated into empty Xe orbitals. Answer: 4.

Question 42

An unknown salt M, when gently heated with concentrated H2SO4 and K2Cr2O7, produces reddish-brown vapours X. These vapours, when passed into NaOH solution, give a yellow solution Y. Yellow precipitate Z is formed on adding Pb(OAc)2 in acetic acid to Y. Based on this reaction scheme, the sa

Accepted Answer

NaBr. X is Br2 (reddish-brown vapour). Br2 + NaOH -> NaBr + NaBrO3 (yellow solution Y). NaBrO3/NaBr + Pb(OAc)2 -> PbBr2 (yellow precipitate Z). This is the bromine test. So M must be a bromide salt: NaBr (option C). NH4Cl+NaBr mixture would also give Br2, but the primary salt listed is NaBr. AgCl has no bromine; Ca(ClO4)2 has no bromine.

Question 43

An unknown compound gives a positive chromyl chloride test and forms a blue solution with potassium ferrocyanide [K4Fe(CN)6]. Identify the compound.

Accepted Answer

FeCl3. Two tests must both be positive: (1) Chromyl chloride test: positive only for chloride (Cl-) compounds — NaCl, CuCl2, FeCl3 pass; FeBr3 fails. (2) Blue color with potassium ferrocyanide K4Fe(CN)6: Fe3+ gives Prussian blue; Cu2+ gives chocolate/brown precipitate (not blue). Therefore FeCl3 satisfies both: it contains Cl- (chromyl chloride test positive) and Fe3+ (blue with K4Fe(CN)6). However, looking at the answer choices and the classic JEE question format, CuCl2 is often cited — but the correct chemistry points to FeCl3. Wait: Cu2+ + K4Fe(CN)6 gives a chocolate brown precipitate (Cu2[

Question 44

Which of the following correctly represents the structure of peroxodisulfuric acid (H2S2O8)?

Accepted Answer

HO-S(=O)2-O-O-S(=O)2-OH. Peroxodisulfuric acid (Marshall's acid, H2S2O8) has the structure: HO-S(=O)2-O-O-S(=O)2-OH. Each sulfur is surrounded by four oxygens (two =O, one -OH, one -O- of the peroxide bridge). The characteristic feature is the -O-O- (peroxide) bond connecting the two SO3(OH) units.

Question 45

Arrange the following oxides in the correct order of increasing acidic strength: SO2, P2O3, SiO2, Al2O3.

Accepted Answer

SO2 > P2O3 > SiO2 > Al2O3. Across period 3, acidic strength of oxides increases from left to right. Al2O3 is amphoteric (least acidic here), SiO2 is a weak acid oxide, P2O3 is a moderate acid oxide, and SO2 is a stronger acid oxide (dissolves in water to give H2SO3). So increasing order of acidic strength: Al2O3 < SiO2 < P2O3 < SO2, i.e., SO2 > P2O3 > SiO2 > Al2O3.

Question 46

Which of the following compounds gives ONLY basic products on hydrolysis?

Accepted Answer

Mg3N2. Mg3N2 + 6H2O → 3Mg(OH)2 + 2NH3. Both Mg(OH)2 (basic) and NH3 (basic) are basic products only. NCl3 + 3H2O → NH3 + 3HOCl (hypochlorous acid is acidic). BBr3 + 3H2O → H3BO3 (weakly acidic) + 3HBr (acidic). PCl5 + 4H2O → H3PO4 (acidic) + 5HCl (acidic). Therefore only Mg3N2 gives exclusively basic products.

Question 47

Which of the following thermal decomposition reactions is written incorrectly?

Accepted Answer

Pb(NO3)2 -> PbO2 + 2NO2 + O2/2 (on heating). The correct decomposition of lead nitrate: 2Pb(NO3)2 -> 2PbO + 4NO2 + O2. PbO2 would not form under these conditions. Options B, C, D are all correct standard reactions. So option A (which gives PbO2) is wrong.

Question 48

Which of the following statements about the heavier p-block elements is correct?

Accepted Answer

All of the above. The inert pair effect makes the lower oxidation states of heavy p-block elements more stable. Tl⁺ is indeed more stable than Tl³+. Pb⁴+ is unstable (prefers Pb²+) so it readily accepts electrons — it is a strong oxidising agent. Bi⁵+ is unstable (prefers Bi³+) so it is also a strong oxidising agent. All three statements are correct.

Question 49

Which cation is NOT precipitated by H2S gas in either acidic medium (group II) or basic/ammoniacal medium (group IV) in qualitative analysis?

Accepted Answer

Ba²+. Pb²+ is precipitated as PbS (black) in Group II (acidic H2S). Zn²+ is precipitated as ZnS (white) in Group IV (H2S in ammoniacal solution). Ag⁺ is typically precipitated in Group I (HCl as AgCl, white), and its sulphide Ag2S can also form in Group II. Ba²+ has a very soluble sulphide (BaS is quite soluble) and is NOT precipitated by H2S in either acidic or basic medium. Barium is separated in Group V using (NH4)2CO3. Hence Ba²+ is the answer.

Question 50

Which of the following gives the correct order of acidic strength?

Accepted Answer

All of the above. Option A: For hypohalous acids HOX, as electronegativity of X decreases (F > Cl > Br > I), the O-H bond becomes weaker (less electron withdrawal from X), so acidity decreases. HOF > HOCl > HOBr > HOI. Correct. Option B: HClO4, HBrO4, HIO4 - all are the strongest oxoacids of respective halogens. Going down group 17, central atom size increases, the O-H bond strength increases relative to element-oxygen bond; acidity of highest oxoacids decreases down the group. HClO4 > HBrO4 > HIO4. Correct. Option C: LiOH is a strong base, Be(OH)2 is amphoteric (weakly basic), B(OH)3 is a wea

JEE Advanced Chemistry: The p-Block Elements questions with solutions

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