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ExamsJEE AdvancedChemistry

An unknown compound gives a positive chromyl chloride test and forms a blue solution with potassium ferrocyanide [K4Fe(CN)6]. Identify the compound.

  1. NaCl
  2. FeBr3
  3. CuCl2
  4. FeCl3

Correct answer: FeCl3

Solution

Two tests must both be positive: (1) Chromyl chloride test: positive only for chloride (Cl-) compounds — NaCl, CuCl2, FeCl3 pass; FeBr3 fails. (2) Blue color with potassium ferrocyanide K4Fe(CN)6: Fe3+ gives Prussian blue; Cu2+ gives chocolate/brown precipitate (not blue). Therefore FeCl3 satisfies both: it contains Cl- (chromyl chloride test positive) and Fe3+ (blue with K4Fe(CN)6). However, looking at the answer choices and the classic JEE question format, CuCl2 is often cited — but the correct chemistry points to FeCl3. Wait: Cu2+ + K4Fe(CN)6 gives a chocolate brown precipitate (Cu2[Fe(CN)6]). Fe3+ + K4Fe(CN)6 gives Prussian blue (Fe4[Fe(CN)6]3). So the correct answer is FeCl3.

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