Exams › JEE Advanced › Chemistry
Correct answer: 4
XeO4 has tetrahedral geometry (4 double bonds, Xe oxidation state +8). Each Xe=O bond consists of one sigma bond and one pi bond formed by overlap of oxygen p orbital with xenon d (or p) orbital — these are p-pi to d-pi bonds. However in the context of p-pi to p-pi bonds, XeO4 is often cited to have 4 such bonds (one per Xe=O bond), using the oxygen lone pair p orbitals donated into empty Xe orbitals. Answer: 4.