Exams › JEE Advanced › Chemistry
Correct answer: Ba²+
Pb²+ is precipitated as PbS (black) in Group II (acidic H2S). Zn²+ is precipitated as ZnS (white) in Group IV (H2S in ammoniacal solution). Ag⁺ is typically precipitated in Group I (HCl as AgCl, white), and its sulphide Ag2S can also form in Group II. Ba²+ has a very soluble sulphide (BaS is quite soluble) and is NOT precipitated by H2S in either acidic or basic medium. Barium is separated in Group V using (NH4)2CO3. Hence Ba²+ is the answer.