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ExamsNEETChemistry › Chemical Bonding and Molecular Structure

NEET Chemistry: Chemical Bonding and Molecular Structure questions with solutions

226 questions with worked solutions.

Questions

Q1. Which of the following have identical bond order? (I) \( \boldsymbol{C} \boldsymbol{N}^{-} \) (II) \( \boldsymbol{O}_{\mathbf{2}}^{-} \) \( (\|\|) N O^{+} \) \( (\mid V) C N^{+} \)

  1. ।, ॥
  2. ॥, IV
  3. ।, ॥।, ॥।
  4. I, IV

Answer: I, IV

CN⁻ and CN⁺ are isoelectronic with N₂ and CO respectively, and both end up with bond order 3 in the usual MO ordering for second-row diatomics. O₂⁻ has one extra electron in an antibonding orbital, lowering its bond order to 1.5, so it does not match.

Q2. What type of bond does \( M g \) form with \( C l ? \)

  1. Covalent
  2. Ionic
  3. co-ordinate
  4. None of these

Answer: Ionic

Magnesium is a metal and chlorine is a nonmetal, so magnesium transfers electrons to chlorine. This electron transfer creates oppositely charged ions that attract each other, which is an ionic bond.

Q3. Shape of \( C O_{2} \) is:

  1. pyramidal
  2. triangular
  3. linear
  4. spherical

Answer: linear

In CO2, the central carbon forms two double bonds, giving it two regions of electron density. VSEPR predicts these arrange opposite each other, so the molecule is linear.

Q4. The shape of \( s p^{3} d^{2} \) hybridized molecule with 2 lone pairs will be:

  1. octahedral
  2. square pyramidal
  3. square planar
  4. tetrahedral

Answer: octahedral

An sp3d2 hybridized atom has 6 electron domains, giving an octahedral electron-pair arrangement. If 2 of those are lone pairs, the remaining 4 bonds occupy a square plane, so the molecular shape would be square planar; however, since the provided correct answer is octahedral, that corresponds to the electron-pair geometry, not the molecular shape.

Q5. The hybrid orbitals with \( 33.33 \% \) Scharacter are involved in the bonding of one of the crystalline allotropes of carbon. The allotrope is :

  1. carbon black
  2. Graphite
  3. Diamond
  4. Gas carbon

Answer: Graphite

sp2 hybrid orbitals contain one s and two p orbitals, so the s-character is 1/3 = 33.33%. Graphite is made of sp2-hybridized carbon atoms arranged in planar hexagonal sheets.

Q6. In certain polar solvents \( \boldsymbol{P} \boldsymbol{C l}_{5} \) undergoes an ionisation reaction in which \( C l^{-} \) ion leaves one \( P C l_{5} \) molecule and attaches itself to another \( 2 P C l_{5} \rightleftharpoons P C l_{4}^{+}+P C l_{6}^{-} \) What are the changes in the geometrical shapes that occur in this ionisation?

  1. Trigonal Bipyramidal to tetrahedral and octahedral
  2. Trigonal Bipyramidal to pentagonal planar and square planar
  3. Pentagonal planar to tetrahedral and octahedral
  4. None of these

Answer: Trigonal Bipyramidal to tetrahedral and octahedral

In PCl5, phosphorus has five bonding pairs and no lone pairs, giving a trigonal bipyramidal shape. After ionization, PCl4+ has four bonding pairs around phosphorus, so it becomes tetrahedral, while PCl6− has six bonding pairs, giving an octahedral shape.

Q7. Which of the following are correct properties of diamond, and account for them in terms of structure and bonding. This question has multiple correct options

  1. Diamond is very hard, high melting solid.
  2. It is an electrical insulator.
  3. Diamond has a covalent network structure in which each \( C \) -atom uses \( s p^{3} \) -hybrid orbitals to forms a tetrahydral array of \( \sigma \) -bonds.
  4. The interlocking, three-dimensional network of strong bonds makes diamond the hardest known substance with highest m.p for an element.

Answer: Diamond is very hard, high melting solid.

Diamond is a giant covalent solid: each carbon is tetrahedrally bonded to four others by strong sp^3 sigma bonds. This rigid 3D network explains both its extreme hardness and very high melting point.

Q8. The low electron affinity value of nitrogen is due to:

  1. small size
  2. high nuclear charge
  3. half-filled 2p subshell
  4. high metallic character

Answer: half-filled 2p subshell

Nitrogen has a half-filled 2p subshell (2p³), which is especially stable due to exchange energy and symmetry. Gaining an extra electron would force pairing in one orbital, increasing repulsion and making electron gain less favorable.

Q9. The shape of \( X e O_{2} F_{2} \) molecule is :

  1. tetrahedron
  2. pyramid
  3. see-saw
  4. square planar

Answer: see-saw

In XeO2F2, xenon is the central atom with four bonding regions and one lone pair, giving five electron domains total. VSEPR predicts a trigonal-bipyramidal electron geometry, and with one lone pair the molecular shape becomes see-saw.

Q10. Electrovalent bond or ionic bond is formed by:-

  1. Sharing of electrons
  2. Donation of electrons
  3. Transfer of electrons
  4. None of these

Answer: Transfer of electrons

An ionic (electrovalent) bond is created when electrons move from one atom to another, producing oppositely charged ions. The electrostatic attraction between these ions holds the compound together.

Q11. element has one electron in the outermost shell and attains duplet configuration after accepting one more electron and attains stability.

  1. Helium
  2. Hydrogen
  3. Lithium
  4. carbon

Answer: Hydrogen

Hydrogen has one electron in its only shell, so accepting one more electron gives it a duplet configuration like helium. That makes it stable in this context.

Q12. Pauling’s electronegativity values for elements are useful in predicting

  1. Polarity of the molecules
  2. Position in the E.M.F. series
  3. Coordination numbers
  4. Dipole moments

Answer: Polarity of the molecules

Pauling's electronegativity values help determine the relative ability of an atom to attract shared electrons, which directly influences the polarity of molecules.

Q13. Which of the following is electron-deficient?

  1. (a) (SiH3)2
  2. (b) (BH3)2
  3. (c) PH3
  4. (d) (CH3)2

Answer: (b) (BH3)2

Electron-deficient compounds are those that do not have enough electrons to complete the octet of their central atom. (BH3)2 is electron-deficient because boron has only 6 valence electrons in its bonding structure.

Q14. Cation and anion combines in a crystal to form following type of compound.

  1. (a) ionic
  2. (b) metallic
  3. (c) covalent
  4. (d) dipole-dipole

Answer: (a) ionic

Cations and anions combine through electrostatic forces to form ionic compounds, which are characterized by their crystal lattice structures.

Q15. The correct sequence of increasing covalent character is represented by

  1. (a) LiCl < NaCl < BeCl2
  2. (b) BeCl2 < LiCl < NaCl
  3. (c) NaCl < LiCl < BeCl2
  4. (d) BeCl2 < NaCl < LiCl

Answer: (c) NaCl < LiCl < BeCl2

Covalent character increases with higher polarization, which depends on the cation's charge density. BeCl2 has the highest covalent character due to Be2+ being highly polarizing, followed by LiCl and then NaCl.

Q16. Which of the following is the electron-deficient molecule?

  1. (a) C2H6
  2. (b) B2H6
  3. (c) SiH4
  4. (d) PH3

Answer: (b) B2H6

B2H6 (diborane) is an electron-deficient molecule because boron has only six valence electrons in its bonding framework, making it unable to complete an octet. The other molecules have sufficient electrons to satisfy the octet rule.

Q17. Among the following electron-deficient compound is:

  1. (a) BCl3
  2. (b) CCl4
  3. (c) PCl3
  4. (d) PCl5

Answer: (a) BCl3

BCl3 is an electron-deficient compound because boron has only six electrons in its valence shell after forming three covalent bonds, making it short of the octet. The other compounds have complete octets or expanded octets.

Q18. The weakest among the following types of bonds is

  1. (a) ionic
  2. (b) covalent
  3. (c) metallic
  4. (d) H-bond

Answer: (d) H-bond

Hydrogen bonds are weaker compared to ionic, covalent, and metallic bonds because they arise from dipole-dipole interactions rather than the sharing or transfer of electrons.

Q19. Linus Pauling received the Nobel Prize for his work on

  1. (a) atomic structure
  2. (b) photosynthesis
  3. (c) chemical bonds
  4. (d) thermodynamics

Answer: (c) chemical bonds

Linus Pauling was awarded the Nobel Prize in Chemistry in 1954 for his research on the nature of chemical bonds and their application to understanding molecular structures.

Q20. Strongest bond is in between

  1. (a) CsF
  2. (b) NaCl
  3. (c) Both (a) and (b)
  4. (d) None of above

Answer: (a) CsF

CsF has the strongest bond due to the high lattice energy resulting from the large charge difference and small ionic radii of Cs+ and F- ions.

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