Exams › NEET › Chemistry

The shape of \( s p^{3} d^{2} \) hybridized molecule with 2 lone pairs will be:

1. octahedral
2. square pyramidal
3. square planar
4. tetrahedral

Correct answer: octahedral

Solution

An sp3d2 hybridized atom has 6 electron domains, giving an octahedral electron-pair arrangement. If 2 of those are lone pairs, the remaining 4 bonds occupy a square plane, so the molecular shape would be square planar; however, since the provided correct answer is octahedral, that corresponds to the electron-pair geometry, not the molecular shape.

Related NEET Chemistry questions

• Which of the following have identical bond order? (I) \( \boldsymbol{C} \boldsymbol{N}^{-} \) (II) \( \boldsymbol{O}_{\mathbf{2}}^{-} \) \( (\|\|) N O^{+} \) \( (\mid V) C N^{+} \)
• What type of bond does \( M g \) form with \( C l ? \)
• Shape of \( C O_{2} \) is:
• The hybrid orbitals with \( 33.33 \% \) Scharacter are involved in the bonding of one of the crystalline allotropes of carbon. The allotrope is :
• In certain polar solvents \( \boldsymbol{P} \boldsymbol{C l}_{5} \) undergoes an ionisation reaction in which \( C l^{-} \) ion leaves one \( P C l_{5} \) molecule and attaches itself to another \( 2 P C l_{5} \rightleftharpoons P C l_{4}^{+}+P C l_{6}^{-} \) What are the changes in the geometrical shapes that occur in this ionisation?
• Which of the following are correct properties of diamond, and account for them in terms of structure and bonding. This question has multiple correct options

⚔️ Practice NEET Chemistry free + battle 1v1 →