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Which of the following have identical bond order? (I) \( \boldsymbol{C} \boldsymbol{N}^{-} \) (II) \( \boldsymbol{O}_{\mathbf{2}}^{-} \) \( (\|\|) N O^{+} \) \( (\mid V) C N^{+} \)

1. ।, ॥
2. ॥, IV
3. ।, ॥।, ॥।
4. I, IV

Correct answer: I, IV

Solution

CN⁻ and CN⁺ are isoelectronic with N₂ and CO respectively, and both end up with bond order 3 in the usual MO ordering for second-row diatomics. O₂⁻ has one extra electron in an antibonding orbital, lowering its bond order to 1.5, so it does not match.

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