Exams › IBPS PO › Quantitative Aptitude
Four years ago, the ratio of the ages of A and B was 3:4. The average of the present ages of A, B, and C is 26 years. C is 11 years younger than B. What is the present age of B?
- 25 years
- 21 years
- 22 years
- 32 years
Correct answer: 32 years
Solution
Let present ages be A = \(a\), B = \(b\), C = \(c\). Since C is 11 years younger than B, \(c=b-11\). Also, \((a+b+c)/3=26\Rightarrow a+b+c=78\). Using the four-years-ago ratio \((a-4):(b-4)=3:4\), we get \(4(a-4)=3(b-4)\). Solving gives \(b=32\).
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