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If 6 years are subtracted from Ayush's present age and 25% of that is taken, we get the present age of his only son. Four years ago, his daughter's age was 7 years more than his son's age. The sum of the daughter's present age and his wife's present age is 10 years more than Ayush's present age. If the average present age of the entire family is 30.25 years, find Ayush's present age.

1. 45 year
2. 50 year
3. 60 year
4. 40 year

Correct answer: 40 year

Solution

Let Ayush's present age be $x$. Then son's age is $\frac{25}{100}(x-6)=\frac{x-6}{4}$. Using the daughter's relation and the wife's relation, and then applying the average age of the four family members, the value of $x$ comes out to be 40 years.

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