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ExamsIBPS POQuantitative Aptitude

A, B, C, D and E are five friends who went to the picnic. Their average age is 43 years. The ratio between the present ages of D and E is 4:5. The ratio between the present ages of A and B is 4:5. Four years from now, the ratio between the age of A and the age of C will be 4:5. Four years from now, A will be 10 years less than the present age of E. Find the average of the ages of D and E.

  1. 45 years
  2. 36 years
  3. 54 years
  4. 60 years

Correct answer: 54 years

Solution

From "four years from now, A will be 10 years less than the present age of E," we get \(A+4=E-10\), so \(E=A+14\). Also, \((A+4):(C+6)=4:5\) gives a relation between A and C. Using the total average age of 43, the sum of all five ages is 215, and solving the system gives \(D+E=108\). Hence the average of D and E is \(108/2=54\) years.

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