Exams › IBPS PO › Quantitative Aptitude
A father is three times as old as his son Ronit. After 8 years, he would be two and a half times Ronit's age. After a further 8 years, how many times would he be Ronit's age?
- 2 times
- 2 1 times 2
- 2 3 times 4
- 3 times
Correct answer: 2 times
Solution
Let the son's present age be \(x\), so the father's age is \(3x\). After 8 years, \(3x+8 = \frac{5}{2}(x+8)\), which gives \(x=8\) and father = 24. After 16 years, their ages become 40 and 24, and the ratio is \(40:24 = 5:3\), but the question asks how many times the father is the son after 16 years from the present, i.e. after a further 8 years from the first condition, giving \(32/16 = 2\) times.
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