Exams › IBPS PO › Quantitative Aptitude

Raman's present age is two-fifths of his father's age. Find Raman's age after 10 years if the sum of their present ages is 63 years.

1. 18 years
2. 20 years
3. 28 years
4. 16 years

Correct answer: 28 years

Solution

Let the father's age be \(x\). Then Raman's age is \(\frac{2}{5}x\), and their sum is 63, so \(x+\frac{2}{5}x=63\). Solving gives Raman's present age as 18, so after 10 years he will be 28.

Related IBPS PO Quantitative Aptitude questions

• A father is three times as old as his son Ronit. After 8 years, he would be two and a half times Ronit's age. After a further 8 years, how many times would he be Ronit's age?
• The sum of the ages of 5 children born at intervals of 3 years each is 50 years. What is the age of the youngest child?
• If 6 years are subtracted from Ayush's present age and 25% of that is taken, we get the present age of his only son. Four years ago, his daughter's age was 7 years more than his son's age. The sum of the daughter's present age and his wife's present age is 10 years more than Ayush's present age. If the average present age of the entire family is 30.25 years, find Ayush's present age.
• The ratio of the ages of A and B is 6:5, and the age of C is 5 years less than twice the age of B. The difference between the ages of C and A is 11 years. What is the age of A?
• The ratio of the present ages of A and B is 6:5. After 10 years, the ratio of their ages will be 7:6. Find the difference in their present ages.
• A, B, C, D and E are five friends who went to the picnic. Their average age is 43 years. The ratio between the present ages of D and E is 4:5. The ratio between the present ages of A and B is 4:5. Four years from now, the ratio between the age of A and the age of C will be 4:5. Four years from now, A will be 10 years less than the present age of E. Find the average of the ages of D and E.

⚔️ Practice IBPS PO Quantitative Aptitude free + battle 1v1 →