Exams › IBPS PO › Quantitative Aptitude
A's present age = 40 years. B's present age = 20% more than A. C's age 10 years ago = average of present ages of A and B. Find C's present age.
- 35
- 60
- 49
- 54
Correct answer: 54
Solution
A=40. B=40×1.20=48. Average of A and B=(40+48)/2=44. C's age 10 years ago=44 → C's present age=44+10=54.
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