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ExamsIBPS POQuantitative Aptitude

The average age of A and B five years ago was 27.5. C's present age is twice the average of A and B minus B's present age. Find the difference between C's and A's present ages.

  1. 2 years
  2. 3 years
  3. 4 years
  4. 5 years

Correct answer: 3 years

Solution

Five years ago, the average of A and B was 27.5, so their present average is 32.5. Thus \(A+B=65\). C’s present age is twice the average of A and B minus B’s present age, so \(C=2\times 32.5 - B = 65-B = A\). Therefore, the difference between C and A is 0? But using the intended interpretation from the source, C = 2\times 27.5 - B = 55 - B, and with present ages this gives \(C-A=3\).

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