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CH3COOH reacts with SOCl2 to form CH3COCl. The product undergoes Friedel Craft reaction with C6H6/AlCl3. The correct option is:

1. CH3COOH + SOCl2 → CH3COCl → Friedel Craft reaction with C6H6/AlCl3
2. CH3COOH + SOCl2 → CH3COCl → Friedel Craft reaction with C6H6/AlCl3 → CH3CH2COOH
3. CH3COOH + SOCl2 → CH3COCl → Friedel Craft reaction with C6H6/AlCl3 → CH3CH2COCl
4. CH3COOH + SOCl2 → CH3COCl → Friedel Craft reaction with C6H6/AlCl3 → CH3CH2COCl + CH3COOH

Correct answer: CH3COOH + SOCl2 → CH3COCl → Friedel Craft reaction with C6H6/AlCl3

Solution

CH3COOH reacts with SOCl2 to form CH3COCl (acetyl chloride). This acetyl chloride undergoes a Friedel-Crafts acylation with benzene (C6H6) in the presence of AlCl3 to form acetophenone (C6H5COCH3).

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