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In an SN2 substitution reaction of the type R–Br + Cl− → R–Cl + Br−, which one of the following has the highest reactivity rate?

1. CH3–CH2–CH2Br
2. CH3–CH–CH2Br | CH3
3. CH3 | CH3–C–CH2Br | CH3
4. CH3CH2Br

Correct answer: CH3CH2Br

Solution

CH3CH2Br has the least steric hindrance, allowing the nucleophile to attack the carbon more easily, leading to the highest reactivity rate.

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