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For (i) I−, (ii) Cl−, (iii) Br−, the increasing order of nucleophilicity would be:
- Cl− < Br− < I−
- Br− < Cl− < I−
- Br− < I− < Cl−
- I− < Br− < Cl−
Correct answer: Cl− < Br− < I−
Solution
Nucleophilicity increases down the group in the periodic table due to the larger size and higher polarizability of the halide ions. Hence, I− is the most nucleophilic, followed by Br−, and then Cl−.
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