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Among the following ethers, which one will produce methyl alcohol on treatment with hot concentrated HI?
- CH₃—CH₂—CH—O—CH₃
- CH₃—C—O—CH₃
- CH₃—CH₂—CH₂—O—CH₃
- CH₃—CH₂—CH₂—O—CH₃
Correct answer: CH₃—CH₂—CH₂—O—CH₃
Solution
When ethers react with hot concentrated HI, cleavage occurs at the C-O bond. In CH₃—CH₂—CH₂—O—CH₃, the bond breaks to form CH₃OH (methyl alcohol) and CH₃CH₂CH₂I.
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