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Which of the following reaction(s) can be used for the preparation of alkyl halides?

1. (I) CH₃CH₂OH + HCl → (anh. ZnCl₂)
2. (II) CH₃CH₂OH + HCl →
3. (III) (CH₃)₃COH + HCl →
4. (IV) (CH₃)₂CHOH + HCl → (anh. ZnCl₂)

Correct answer: (I) CH₃CH₂OH + HCl → (anh. ZnCl₂)

Solution

Reaction (I) and (IV) involve the use of anhydrous ZnCl₂, which acts as a catalyst in the Lucas test for alcohols, facilitating the preparation of alkyl halides. Reaction (III) also proceeds due to the tertiary alcohol's high reactivity with HCl. Reaction (II) lacks ZnCl₂ and is less efficient.

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