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ExamsNEETChemistry

When CH3CH2CH2Cl is treated with NaNH2, the product formed is:

  1. CH3—CH=CH2
  2. CH3—C≡CH
  3. CH3CH2CH=NH2
  4. CH3CH2CH2NH2

Correct answer: CH3—C≡CH

Solution

When CH3CH2CH2Cl reacts with NaNH2, elimination occurs, leading to the formation of a terminal alkyne (CH3—C≡CH) via dehydrohalogenation.

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