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When CH3CH2CH2Cl is treated with NaNH2, the product formed is:
- CH3—CH=CH2
- CH3—C≡CH
- CH3CH2CH=NH2
- CH3CH2CH2NH2
Correct answer: CH3—C≡CH
Solution
When CH3CH2CH2Cl reacts with NaNH2, elimination occurs, leading to the formation of a terminal alkyne (CH3—C≡CH) via dehydrohalogenation.
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