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The reaction: CH3(CH2)3–C–Br + OH⁻ → CH3(CH2)3–C–OH is described as

1. Sₙ2
2. Sₙ1
3. Sₙ0
4. Sₙ2'

Correct answer: Sₙ1

Solution

The reaction involves the substitution of Br⁻ by OH⁻ in a tertiary alkyl halide, which proceeds via the Sₙ1 mechanism due to the formation of a stable carbocation intermediate.

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