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CH3–CH2–CH–CH3 obtained by chlorination of n-butane, will be

1. l-form
2. d-form
3. Meso form
4. Racemic mixture

Correct answer: Racemic mixture

Solution

Chlorination of n-butane at the secondary carbon produces a chiral center. Since the reaction is non-stereoselective, it results in equal amounts of both enantiomers, forming a racemic mixture.

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