Exams › GATE › Technical › GATE 2022 Electrical Engineering (EE)
14 questions with worked solutions.
Answer: infinite
For an ideal MOSFET the gate (input) current is zero, so the small-signal input current of a common-drain (source-follower) stage is essentially zero while the output current is finite. The current gain (output/input) is therefore infinite.
Q2. The most commonly used relay, for the protection of an alternator against loss of excitation, is
Answer: offset Mho relay.
The offset Mho relay is specifically designed to detect loss of excitation in alternators by monitoring the impedance of the generator, making it the most effective choice for this protection scenario.
Answer: 1.723 r
The geometric mean radius for a conductor with multiple strands is calculated using the formula that accounts for the arrangement of the strands. In this case, with four equal strands, the geometric mean radius is determined to be approximately 1.723 times the radius of a single strand.
Answer: one LHP pole and one RHP zero at the same frequency.
The system exhibits a constant magnitude in the Bode plot, indicating a first-order behavior, while the high-frequency phase of -180° suggests the presence of a zero that cancels out the effect of a pole, resulting in one left-half plane (LHP) pole and one right-half plane (RHP) zero at the same frequency.
Answer: 20∠30°
The correct option is 20∠30° because for the voltage difference across nodes n and n' to be zero in a star-connected load, the sum of the phase currents must equal zero. By calculating the phase currents for the given impedances and ensuring they balance out, we find that Z_C must be 20∠30° to achieve this condition.
Answer: MOSFET
MOSFETs are ideal for high-frequency applications like this one due to their fast switching capabilities and low on-resistance, making them efficient for power conversion at 200 kHz.
Answer: Jₐ/5 r⁴
Enclosed current I(r) = integral_0^r (Ja r'^3)(2*pi*r') dr' = 2*pi*Ja*r^5/5. Then H = I/(2*pi*r) = Ja*r^4/5. Stored answer (Ja/4 r^4) is wrong; the correct one is Ja r^4 /5.
Answer: capacitor start, capacitor run.
The capacitor start, capacitor run motor is designed to improve both starting torque and efficiency, resulting in a higher power factor during steady state operation compared to other types of single-phase induction motors.
Answer: (C) log(|Z_out|) versus log(f) is low at first, then increases to a higher constant value
The correct option indicates that as frequency increases, the output impedance initially remains low due to the operational amplifier's feedback mechanisms, but eventually rises to a higher constant value as the effects of parasitic capacitances and other frequency-dependent factors become significant.
Answer: a = 1, b = 10
The steady state output of an LTI system to a sinusoidal input can be determined using the system's frequency response. For the given transfer function, at the frequency of the input (10 rad/s), the output has a DC component of 1 and an amplitude of 10 for the sinusoidal part, leading to the values a = 1 and b = 10.
Answer: 250, 300
Plant 1: dC1/dP1 = 6 + 0.008 P1 = 8 gives P1 = 250 MW. With total demand 550 MW, P2 = 300 MW (consistent with a + 0.006(300) = 8). The optimal dispatch is 250 MW and 300 MW, option (250, 350) being wrong; correct is (250, 300).
Answer: 12
J=curl H gives Jx=2x^2 y z^2, Jy=-2x y^2 z^2, Jz=2x y^2. At (1,2,1): J=(4,-8,8), so |J|=sqrt(16+64+64)=12 A/m^2.
Answer: 8e^(-4t)u(t)
The equation y + (1/4)dy/dt = 2x becomes dy/dt + 4y = 8x. The transfer function is 8/(s+4), so the impulse response is 8e^(-4t)u(t). This is option 3, not the stored option 0.
Answer: V(r) = cd(V1 − V2)/((d − c)r) + (V2 d − V1 c)/(d − c)
The correct option is derived from the principles of electrostatics, where the potential difference between two points in a radial electric field is expressed in terms of the distances and potentials at the boundaries. This option correctly accounts for the linear variation of potential in the region between the two spherical shells, ensuring that it satisfies the boundary conditions set by the potentials at r = c and r = d.