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If the magnetic field intensity (H) in a conducting region is given by the expression, H = x² î + x² y² ĵ + x² y² z² k̂ A/m. The magnitude of the current density, in A/m², at x = 1 m, y = 2 m and z = 1 m, is
- 8
- 12
- 16
- 20
Correct answer: 12
Solution
J=curl H gives Jx=2x^2 y z^2, Jy=-2x y^2 z^2, Jz=2x y^2. At (1,2,1): J=(4,-8,8), so |J|=sqrt(16+64+64)=12 A/m^2.
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