Exams › SSC CGL (Prelims) › General

If \(\cos A = \frac{5}{13}\) and \(A\) is acute, find \(\tan(90^\circ - A)\).

1. 12/5
2. 5/12
3. 13/12
4. 12/13

Correct answer: 5/12

Solution

Since \(\cos A=5/13\) and \(A\) is acute, \(\sin A=12/13\). Now \(\tan(90^\circ-A)=\cot A=\frac{\cos A}{\sin A}=\frac{5/13}{12/13}=5/12\).

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