Exams › SSC CGL (Prelims) › General
Correct answer: 12/5
Since \(A+B=90^\circ\), we have \(\tan B=\cot A\). Given \(\cos A=5/13\), \(\sin A=12/13\), so \(\cot A=\frac{\cos A}{\sin A}=\frac{5}{12}\).
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