If $\sin^2\theta-\cos^2\theta=-\frac{1}{3}$, find the value of $\cos^2\theta$.
$1/3$
$1/2$
$2/3$
$5/6$
Correct answer: $2/3$
Solution
Using $\sin^2\theta=1-\cos^2\theta$, we get $(1-\cos^2\theta)-\cos^2\theta=-\frac13$. This gives $1-2\cos^2\theta=-\frac13$, so $\cos^2\theta=\frac23$.