Exams › SSC CGL (Prelims) › General

If \(\tan B = \cot(4B - 45^\circ)\), what is \(B\)?

1. 20°
2. 25°
3. 30°
4. 27°

Correct answer: 27°

Solution

Using \(\cot x = \tan(90^\circ-x)\), we get \(\tan B = \tan(135^\circ - 4B)\). Hence \(B = 135^\circ - 4B\) (principal value), so \(5B=135^\circ\) and \(B=27^\circ\).

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