Exams › SSC CGL (Prelims) › General
Correct answer: 45°
Since \(\cot \theta = \frac{1}{\tan \theta}\), the equation becomes \(\tan \theta = \frac{1}{\tan \theta}\). So \(\tan^2 \theta = 1\), giving \(\tan \theta = 1\) for the standard acute-angle solution. Hence \(\theta = 45^\circ\).