Exams › SSC CGL (Prelims) › General

If $\sec A = y$, then what is $\tan^2 A$ in terms of $y$?

1. $1-y^2$
2. $y^2-1$
3. $1+y^2$
4. $2y^2-1$

Correct answer: $y^2-1$

Solution

Since $\sec A=y$, we have $\sec^2 A=y^2$. Using the identity $\sec^2 A=1+\tan^2 A$, it follows that $\tan^2 A=y^2-1$.

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