Exams › SSC CGL (Prelims) › General

A pole of length \(L\) casts a shadow on the ground. A wire is stretched from the top of the pole to the tip of the shadow, making a \(60^\circ\) angle with the ground. If the pole is 12 metres high, find the approximate length of the wire.

1. 10 m
2. 18 m
3. 16 m
4. 14 m

Correct answer: 14 m

Solution

The pole, shadow, and wire form a right triangle. Since the wire makes a \(60^\circ\) angle with the ground, \(\sin 60^\circ = \frac{12}{\text{wire}}\). So wire \(= \frac{12}{\sin 60^\circ} = \frac{24}{\sqrt{3}} \approx 13.9\) m, which is about 14 m.

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