Exams › SSC CGL (Prelims) › General
Correct answer: \(\sqrt{2}\sin A\)
From \(\cos A + \sin A = \sqrt{2}\cos A\), we get \(\sin A = (\sqrt{2}-1)\cos A\). Substituting into \(\cos A - \sin A\) and simplifying gives the required expression. The result matches the standard form obtained from the given relation.