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A man standing on the top of a 150 m high tower observes the angles of depression of two cars on opposite sides of the tower to be $30^\circ$ and $60^\circ$. What is the distance between the two cars?
- 200 $\sqrt{3}$ m
- 150 $\sqrt{3}$ m
- 100 $\sqrt{3}$ m
- 300 m
Correct answer: 200 $\sqrt{3}$ m
Solution
For the car seen at $30^\circ$, horizontal distance from the tower is $150\cot 30^\circ = 150\sqrt{3}$. For the car seen at $60^\circ$, it is $150\cot 60^\circ = 50\sqrt{3}$. Since they are on opposite sides, the distance between them is $150\sqrt{3}+50\sqrt{3}=200\sqrt{3}$ m.
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