Exams › SSC CGL (Prelims) › General
Correct answer: 60°
In the right triangle formed by the tower and its shadow, $\tan\theta = \frac{\text{height}}{\text{shadow}} = \frac{15\sqrt{3}}{15} = \sqrt{3}$. Since $\tan 60^\circ = \sqrt{3}$, the angle of elevation is $60^\circ$.