Exams › SSC CGL (Prelims) › General
Correct answer: 24/25
Using \((\sin A+\cos A)^2=\sin^2A+\cos^2A+2\sin A\cos A=1+2\sin A\cos A\). Since \(\sin A+\cos A=\frac{7}{5}\), we get \(\frac{49}{25}=1+2\sin A\cos A\), so \(2\sin A\cos A=\frac{24}{25}\). Hence \(\sin 2A=\frac{24}{25}\).