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Power dissipated in series LCR: P = I²R = e² / (Z)² × R = e²R / [R² + (ωL - 1 / ωC)²].

1. P = e²R / [R² + (ωL - 1 / ωC)²]
2. P = e²R / [R² - (ωL - 1 / ωC)²]
3. P = e²R / [R² + (ωL + 1 / ωC)²]
4. P = e²R / [R² - (ωL + 1 / ωC)²]

Correct answer: P = e²R / [R² + (ωL - 1 / ωC)²]

Solution

The correct formula for power dissipated in an LCR circuit is derived using the impedance Z = √(R² + (ωL - 1/ωC)²). Substituting Z² into the power formula P = e²R / Z² gives the correct expression as P = e²R / [R² + (ωL - 1/ωC)²].

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